If a cast from void* to a struct type pointer fails

[William Payne]

Hello!
If a cast from a void pointer to a pointer to a struct fails at runtime, is
NULL the result? I.E, is this code meaningful:

struct my_struct_t foo* = (struct my_struct_t*)vo id_pointer;
// void_pointer is of type void*
if(foo == NULL)
{
printf("Error!\ n");
}

/ William Payne

[Artie Gold]

William Payne wrote:

Hello!
If a cast from a void pointer to a pointer to a struct fails at runtime, is
What do you mean by `fails'?
NULL the result? I.E, is this code meaningful:

struct my_struct_t foo* = (struct my_struct_t*)vo id_pointer;
Do you perhaps mean:

struct my_struct_t *foo - (struct my_struct_t *)void_pointer;
// void_pointer is of type void*
if(foo == NULL)
{
printf("Error!\ n");
}

With the correction above, sure -- iff `void_pointer' was NULL to begin
with and originated as a pointer to `struct my_struct_t'.

I think you either have another question here -- or it's time to OTDB!*

HTH,
--ag

* - Open The Damn Book
--
Artie Gold -- Austin, Texas

"Yeah. It's an urban legend. But it's a *great* urban legend!"

[Arthur J. O'Dwyer]

On Sat, 14 Feb 2004, William Payne wrote:

If a cast from a void pointer to a pointer to a struct fails at
runtime, is NULL the result? I.E, is this code meaningful:

struct my_struct_t foo* = (struct my_struct_t*)vo id_pointer;

First of all, it's not correct, because there are syntax errors
on it. Fixing the errors, and getting rid of the spurious cast
(which serves only to shut up the compiler about errors; casts
almost never solve problems), we have

| struct my_struct_t *foo = void_pointer;

If 'void_pointer' is pointing at a 'struct my_struct_t', or is
a null pointer, then this will work in the obvious fashion.
Otherwise, this line invokes undefined behavior. For example,

int i;
void *p = &i;
struct my_struct_t *foo = void_pointer;

This is undefined behavior and can do anything it likes (including
possibly setting 'foo' to NULL, but more likely setting it to a
nonsense value, rounding it to a "close-enough" value, or raising
a bus error).

struct my_struct_t s;
void *p = &s;
struct my_struct_t *foo = void_pointer;

This is defined behavior, and 'foo' now points to 's'.

HTH,
-Arthur

[Artie Gold]

Artie Gold wrote:

William Payne wrote:

Hello!
If a cast from a void pointer to a pointer to a struct fails at
runtime, is

What do you mean by `fails'?

NULL the result? I.E, is this code meaningful:

struct my_struct_t foo* = (struct my_struct_t*)vo id_pointer;

Do you perhaps mean:

struct my_struct_t *foo - (struct my_struct_t *)void_pointer;

= (of course)

// void_pointer is of type void*
if(foo == NULL)
{
printf("Error!\ n");
}

With the correction above, sure -- iff `void_pointer' was NULL to begin
with and originated as a pointer to `struct my_struct_t'.

I think you either have another question here -- or it's time to OTDB!*

HTH,
--ag

* - Open The Damn Book

--
Artie Gold -- Austin, Texas

"Yeah. It's an urban legend. But it's a *great* urban legend!"

[Christopher Benson-Manica]

Arthur J. O'Dwyer <aj*@nospam.and rew.cmu.edu> spoke thus:

If a cast from a void pointer to a pointer to a struct fails at
runtime, is NULL the result? I.E, is this code meaningful:

struct my_struct_t foo* = (struct my_struct_t*)vo id_pointer;

First of all, it's not correct, because there are syntax errors
on it. Fixing the errors, and getting rid of the spurious cast
(which serves only to shut up the compiler about errors; casts
almost never solve problems), we have | struct my_struct_t *foo = void_pointer;

Is it possible that the OP was thinking in the C++ world, which (IIRC)
requires the cast of void_pointer? Perhaps he was looking for
something like dynamic_cast that throws an exception when it "fails"
at runtime? Just a (probably wrong and definitely OT) thought.

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cybers pace.org | don't, I need to know. Flames welcome.