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why this program is incorrect?

Hi,

I am trying to get the iterator that points to the last element of a
deque.
However, the following program is incorrect:

#include <deque>
#include <iostream>
using namespace std;

int main()
{
deque<int> queue;
deque<int>::ite rator it;

queue.clear();
queue.push_back (5);
it = queue.rbegin(). base();

cout<<"*it = "<<*it<<end l;
return 0;
}

How can I get a correct one?
Thanks a lot!

Andy

Jul 23 '05 #1
4 1132
well, it = (queue.rbegin() + 1).base() will work.
andy

Jul 23 '05 #2
Andy wrote:
I am trying to get the iterator that points to the last element of a
deque.


/**/ std::deque<int> queue;
/**/ queue.push_back (5);
/**/ std::deque<int> ::iterator it = queue.end() - 1;
--
<mailto:di***** ******@yahoo.co m> <http://www.dietmar-kuehl.de/>
<http://www.contendix.c om> - Software Development & Consulting

Jul 23 '05 #3
On 2005-02-01 09:39:31 -0500, "Andy" <gn***@yahoo.co m> said:
well, it = (queue.rbegin() + 1).base() will work.
andy


Why even bother with reverse iterators? Why not just use:

it = queue.end() - 1;

--
Clark S. Cox, III
cl*******@gmail .com

Jul 23 '05 #4
Andy wrote:
Hi,

I am trying to get the iterator that points to the last element of a
deque.
However, the following program is incorrect:

#include <deque>
#include <iostream>
using namespace std;

int main()
{
deque<int> queue;
deque<int>::ite rator it;

queue.clear();
queue.push_back (5);
it = queue.rbegin(). base();

cout<<"*it = "<<*it<<end l;
return 0;
}

How can I get a correct one?
Thanks a lot!

Andy


Hi,

base() returns an iterator one beyond the element pointed to by the
corresponding reverse_iterato r so you need

it = --(queue.rbegin() .base());

instead.

/Andreas

Jul 23 '05 #5

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