I'm sure there's a fairly easy answer for this... but how can I define a new
type with range checking?
Example: I want to define a new type that's like a double, except that you
can only give it values from 0.0 to 100.0. I'd also like it to act like a
double as much as possible, except that an exception is thrown when it's set
to an invalid number.
Ideas?
Thanks,
Joe 10 1865
* Joe Laughlin: I'm sure there's a fairly easy answer for this... but how can I define a new type with range checking?
Example: I want to define a new type that's like a double, except that you can only give it values from 0.0 to 100.0. I'd also like it to act like a double as much as possible, except that an exception is thrown when it's set to an invalid number.
Ideas?
The difference between original C++ and C was that C++ had classes.
A class is a type.
To define a new type, define a class.
Supply the operations you want the type to have.
Get yourself a good C++ book, e.g. "Accelerate d C++".
--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
Joe Laughlin wrote: I'm sure there's a fairly easy answer for this... but how can I define a new type with range checking?
Example: I want to define a new type that's like a double, except that you can only give it values from 0.0 to 100.0. I'd also like it to act like a double as much as possible, except that an exception is thrown when it's set to an invalid number.
Ideas?
This google groups link points to a recent discussion on comp.std.c++. http://tinyurl.com/6zyg9
Joe Laughlin posted: I'm sure there's a fairly easy answer for this... but how can I define a new type with range checking?
Example: I want to define a new type that's like a double, except that you can only give it values from 0.0 to 100.0. I'd also like it to act like a double as much as possible, except that an exception is thrown when it's set to an invalid number.
Ideas?
Thanks, Joe
Use your brain:
class RestrictiveDoub le
{
public: class bad_proposal {};
private:
double data;
Set(double const proposed)
{
if (propose > 100 || proposed < 0) throw bad_proposal;
data = proposed;
}
public:
RestrictiveDoub le& operator=(doubl e const proposed)
{
Set(proposed);
}
//Copy constructor is unnecessary
//Put a constructor here
//Put an operator double here
};
I would've finished it for you, but then half way through I thought it may
have been homework for you.
-JKop
JKop wrote: Joe Laughlin posted:
I'm sure there's a fairly easy answer for this... but how can I define a new type with range checking?
Example: I want to define a new type that's like a double, except that you can only give it values from 0.0 to 100.0. I'd also like it to act like a double as much as possible, except that an exception is thrown when it's set to an invalid number.
Ideas?
Thanks, Joe
Use your brain:
class RestrictiveDoub le { public: class bad_proposal {};
private:
double data;
Set(double const proposed) { if (propose > 100 || proposed < 0) throw bad_proposal;
data = proposed; }
public:
RestrictiveDoub le& operator=(doubl e const proposed) { Set(proposed); }
//Copy constructor is unnecessary
//Put a constructor here
//Put an operator double here
}; I would've finished it for you, but then half way through I thought it may have been homework for you.
-JKop
What's an "operator double"? And I'm confused why you are defining a class
bad_proposal inside of RestrictiveDoub le, and then throwing it. What's an "operator double"? And I'm confused why you are defining a class bad_proposal inside of RestrictiveDoub le, and then throwing it.
Sorry, I'd like to help you, but I still suspect that this is some sort of
homework question.
If you have a decent book on C++, then go to the chapter on "operator
overloading", the conversion operators will be in there with it.
As regards defining one class within another: All it means is that, instead
of the class's name being "bad_propos al", its name is
"RestrictiveDou ble::bad_propos al". Also, if I were to define the
"bad_propos al" class within the private section of the "RestrictiveDou ble"
class definition, then it would be inaccessible from outside of the class's
own code. (Also I wouldn't be able to throw it as the caller wouldn't be
able to play with it).
-JKop
JKop wrote: What's an "operator double"? And I'm confused why you are defining a class bad_proposal inside of RestrictiveDoub le, and then throwing it. Sorry, I'd like to help you, but I still suspect that this is some sort of homework question.
Not homework.
If you have a decent book on C++, then go to the chapter on "operator overloading", the conversion operators will be in there with it.
I understand about operator overloading, just never heard of "operator
double". I've only heard of the usual operator==, operator>>, etc. As regards defining one class within another: All it means is that, instead of the class's name being "bad_propos al", its name is "RestrictiveDou ble::bad_propos al". Also, if I were to define the "bad_propos al" class within the private section of the "RestrictiveDou ble" class definition, then it would be inaccessible from outside of the class's own code. (Also I wouldn't be able to throw it as the caller wouldn't be able to play with it).
-JKop I understand about operator overloading, just never heard of "operator double". I've only heard of the usual operator==, operator>>, etc.
Here's the jist of it:
class Blah
{
public:
operator bool() const
{
return true;
}
};
void SomeFunc(bool const monkey)
{
}
intm main()
{
Blah blah_object;
SomeFunc(blah_o bject);
}
JKop wrote: I understand about operator overloading, just never heard of "operator double". I've only heard of the usual operator==, operator>>, etc.
Here's the jist of it:
class Blah { public:
operator bool() const { return true; } };
void SomeFunc(bool const monkey) {
}
intm main() { Blah blah_object;
SomeFunc(blah_o bject); }
So, you can use Blah anywhere you can use a bool?
Joe Laughlin posted: JKop wrote: I understand about operator overloading, just never heard of "operator double". I've only heard of the usual operator==, operator>>, etc.
Here's the jist of it:
class Blah { public:
operator bool() const { return true; } };
void SomeFunc(bool const monkey) {
}
intm main() { Blah blah_object;
SomeFunc(blah_o bject); }
So, you can use Blah anywhere you can use a bool?
Yep, for instance:
while (blah_object)
{
;
}
if (blah_object) ;
-JKop This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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