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file open error

Hello everybody,

I am getting a "segmentati on fault" error when i compile the following
piece of code. The program runs fine till it encounters the line of
code saying" FILE_lic=fopen. ........". And after that, it terminates
saying segmentation fault. I had included the appropriate header files
also! I couldn't makeout where the problem exists in the program. Can
anyone solve this mistery!
void LICENSEinfo::fi nd()
{
char check[10],vendor[20],date[12];
char uw1[20],uw2[20],mystring[200];
int lic_num;
char filestring[20];

struct dirent *dp, *subdp;
DIR *dir, *subdir;

FILE *FILE_list;
FILE *FILE_lic;

FILE_list = fopen("/tmp/list","w");

// Make "/parent" as the present working directory
chdir ("/parent");

dir=opendir("." );
while ((dp=readdir(di r))!=NULL)
{
if(!strcmp(dp->d_name,".")||! strcmp(dp->d_name,"..") )
continue;

subdir=opendir( dp->d_name);
while ((subdp=readdir (subdir))!=NULL )
{
if(!strcmp(subd p->d_name,".")||! strcmp(subdp->d_name,"..") )
continue;

if(strstr(subdp->d_name,"_lic") !=0)
{

// read the entire file
strcpy(filestri ng,subdp->d_name);
FILE_lic = fopen(filestrin g,"r");
// problem: FILE_lic is reset to 0x0 here.
while (feof(FILE_lic) ==0)
{
fgets(mystring, 200,FILE_lic);
if((strstr(myst ring,"INCREMENT "))||(strstr(my string,"FEATURE ")))
{
sscanf(mystring ,"%s%s%s%s%s%d" ,check,uw1,vend or,uw2,date,&li c_num);
fprintf (FILE_list,"%s \t %s \t %d \n",vendor,date ,lic_num);
}
}

}

}
}

}


Thanks in advance
Jul 22 '05 #1
2 5451
Hi,

"Abhijit" <ab*********@ya hoo.com> wrote in message
news:45******** *************** **@posting.goog le.com...
Hello everybody,

I am getting a "segmentati on fault" error when i compile the following
piece of code. The program runs fine till it encounters the line of
code saying" FILE_lic=fopen. ........". And after that, it terminates
saying segmentation fault. I had included the appropriate header files
also! I couldn't makeout where the problem exists in the program. Can
anyone solve this mistery!
void LICENSEinfo::fi nd()
{
char check[10],vendor[20],date[12];
char uw1[20],uw2[20],mystring[200];
int lic_num;
char filestring[20];

struct dirent *dp, *subdp;
DIR *dir, *subdir;

FILE *FILE_list;
FILE *FILE_lic;

FILE_list = fopen("/tmp/list","w");

// Make "/parent" as the present working directory
chdir ("/parent");

dir=opendir("." );
while ((dp=readdir(di r))!=NULL)
{
if(!strcmp(dp->d_name,".")||! strcmp(dp->d_name,"..") )
continue;

subdir=opendir( dp->d_name);
while ((subdp=readdir (subdir))!=NULL )
{
if(!strcmp(subd p->d_name,".")||! strcmp(subdp->d_name,"..") )
continue;

if(strstr(subdp->d_name,"_lic") !=0)
{

// read the entire file
strcpy(filestri ng,subdp->d_name);
FILE_lic = fopen(filestrin g,"r");
In the current directory there isn't a file with the contents of
subdp->d_name. Hence fopen can't find the file and returns 0.

You should first change with chdir to the child directory you are reading
from. Though you opened the subdir for reading with readdir, your working
directory is still set to the parent of the subdir.

Regards, Ron AF Greve.
// problem: FILE_lic is reset to 0x0 here.
while (feof(FILE_lic) ==0)
{
fgets(mystring, 200,FILE_lic);
if((strstr(myst ring,"INCREMENT "))||(strstr(my string,"FEATURE ")))
{
sscanf(mystring ,"%s%s%s%s%s%d" ,check,uw1,vend or,uw2,date,&li c_num);
fprintf (FILE_list,"%s \t %s \t %d \n",vendor,date ,lic_num);
}
}

}

}
}

}


Thanks in advance

Jul 22 '05 #2
Abhijit wrote:
Hello everybody,

I am getting a "segmentati on fault" error when i compile the following
piece of code. The program runs fine till it encounters the line of
code saying" FILE_lic=fopen. ........". And after that, it terminates
saying segmentation fault. I had included the appropriate header files
also! I couldn't makeout where the problem exists in the program. Can
anyone solve this mistery!
FILE_lic = fopen(filestrin g,"r");
// problem: FILE_lic is reset to 0x0 here.

Do you understand what it means when the return value from fopen() is
0? If not, why not? What book are you using?

Do you understand that FILE_lic is a pointer? Do you understand what
happens if you attempt to use a null pointer? If not, why not?

Brian Rodenborn
Jul 22 '05 #3

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