Hi,
I'm having a problem understanding the reason for output on the
following code:
#include <iostream.h>
int main()
{
char array[]={'w','e','l',' c','o','m','e'} ;
cout<<array<<en dl;
return 0;
}
When i run this, the output is something like this:
welcome¦+*?
Will appreciate some help on understanding the concept.
Thanks,
ali 8 2737
"ali" <tj@raha.com> wrote in message
news:t3******** *************** *********@4ax.c om... Hi,
I'm having a problem understanding the reason for output on the following code:
#include <iostream.h>
int main() {
char array[]={'w','e','l',' c','o','m','e'} ;
cout<<array<<en dl;
return 0; }
When i run this, the output is something like this:
welcome¦+ ?
Will appreciate some help on understanding the concept.
Thanks,
ali
Strings require a null terminator, which you are missing. This is character
'\0'.
ali wrote: char array[]={'w','e','l',' c','o','m','e'} ;
cout<<array<<en dl;
return 0; }
When i run this, the output is something like this:
welcome?+ ?
Will appreciate some help on understanding the concept.
C-style strings are array of chars zero terminated. You have an array of
char that is not zero terminated. "cout <<" when passed an array of char
supposes that it is a c-style string, the in that case it continues writing
anything has in memory after the array, interpreted as chars, until a 0 is
found.
--
Salu2
* ali: #include <iostream.h>
Should be
#include <iostream>
'iostream.h' is not a standard C++ header. It was common before
standardization in 1996 (or 1997, depending on one's point of view).
int main() {
char array[]={'w','e','l',' c','o','m','e'} ;
Preferably make that an array of 'const' characters unless you mean
to change the contents, i.e.
char const array[] = { 'w','e','l','c' ,'o','m','e' }; cout<<array<<en dl;
std::cout << array << std::endl; return 0; }
When i run this, the output is something like this:
welcome¦+*?
Will appreciate some help on understanding the concept.
That's because operator<< assumes a character array is a sequence
of characters terminated by a zero byte, '\0'. You don't have a
zero byte at the end. So operator<< continues writing characters
(garbage memory content) until by chance it encounters a zero byte.
You could do it this way:
for( unsigned i = 0; i < sizeof(array); ++i )
{
std::cout << array[i];
}
std::cout << std::endl;
or, leveraging support in the standard library, but less easy to
understand what happens behind the scenes,
#include <iostream> // std::cout
#include <iterator> // std::ostream_it erator
#include <algorithm> // std::copy
int main()
{
char const array[] = { 'w','e','l','c' ,'o','m','e' };
std::copy(
array, array + sizeof( array ),
std::ostream_it erator<char>( std::cout )
);
std::cout << std::endl;
}
--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
On Fri, 06 Aug 2004 16:02:27 -0700, Alf P. Steinbach wrote: 'iostream.h' is not a standard C++ header. It was common before standardization in 1996 (or 1997, depending on one's point of view).
How about 1998? :) The first edition of the standard document is dated
1998-09-01.
I remembered the subject of the comp.lang.c++.m oderated post that broke
the news to the C++ community: "We have a standard!". Even though I found
the tail end of that thread (posted around August 1998), on
groups.google.c om, the original message is missing.
Ali
"ali" <tj@raha.com> wrote in message
news:t3******** *************** *********@4ax.c om... Hi,
I'm having a problem understanding the reason for output on the following code:
#include <iostream.h>
int main() {
char array[]={'w','e','l',' c','o','m','e'} ;
cout<<array<<en dl;
return 0; }
When i run this, the output is something like this:
welcome¦+ ?
In addition to what everyone else will tell you, I'd like to add that C
strings must be terminated by a null ('\0'). Just in case that message
doesn't get through.
--
Mabden\0
ali wrote: Hi,
I'm having a problem understanding the reason for output on the following code:
#include <iostream.h>
int main() {
char array[]={'w','e','l',' c','o','m','e'} ;
cout<<array<<en dl;
return 0; }
When i run this, the output is something like this:
welcome?+*?
Will appreciate some help on understanding the concept.
Thanks,
ali
You're missing the terminating null character '\0'
On Fri, 06 Aug 2004 18:42:55 -0400, ali <tj@raha.com> wrote: Hi,
I'm having a problem understanding the reason for output on the following code:
#include <iostream.h>
int main() {
char array[]={'w','e','l',' c','o','m','e'} ;
cout<<array<<en dl;
return 0; }
When i run this, the output is something like this:
welcome¦+Â*?
Will appreciate some help on understanding the concept.
Thanks,
ali
Change your array to this
char array[]={'w','e','l',' c','o','m','e', '\0'};
or this
char array[]="welcome";
Those are two different ways to add the nul terminateor that everyoe else
has told you about.
john
David Theese wrote: Strings require a null terminator, which you are missing. This is character '\0'.
But note that \0 is not a special escape sequence for nul, it's just an
ordinary octal escape sequence with only one digit. This can make a
difference for the rare case of inserting a nul in the middle of a
string constant.
"\087" is four characters but "\076" is only two.
-josh This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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