remove_if and functions overloading

[marco_segurini]

Hi,

if I compile the following code I get the error:

RemoveIf.cpp(19 ) : error C2914: 'remove_if' : cannot deduce template
argument as function argument is ambiguous

#include <algorithm>
#include <vector>

template<typena me T>
class vector_t
: public std::vector<T>
{
bool TestRemove(long Pos) const //(1)
{
return false;
}
static bool TestRemove(cons t T &) //(2)
{
return false;
}
public:
void RemoveIf()
{
erase(std::remo ve_if(begin(), end(), &vector_t<T>::T estRemove),
end()); //this is line 19
}
};

typedef struct point
{
long x;
long y;
long f;
} point;

int main()
{
vector_t<point> vp;
vp.RemoveIf();

return 0;
}
How may I force the remove_if to use the TestRemove (2) function as
predicate?

TIA.
Marco.

[tom_usenet]

On 7 Apr 2004 02:52:48 -0700, ma***********@v irgilio.it
(marco_segurini ) wrote:

Hi,

if I compile the following code I get the error:

RemoveIf.cpp(1 9) : error C2914: 'remove_if' : cannot deduce template
argument as function argument is ambiguous

#include <algorithm>
#include <vector>

template<typen ame T>
class vector_t
: public std::vector<T>
{
bool TestRemove(long Pos) const //(1)
{
return false;
}
static bool TestRemove(cons t T &) //(2)
{
return false;
}
public:
void RemoveIf()
{
bool (*remover)(cons t T&) = &vector_t<T>::T estRemove;
erase(std::remo ve_if(begin(), end(), remover),
end()); //this is line 19
How may I force the remove_if to use the TestRemove (2) function as
predicate?

Either the above, or add a static cast to select the function type:

erase(
std::remove_if(
begin(),
end(),
static_cast<boo l (*)(const T&)>(&vector_t< T>::TestRemove )
),
end()
);

When taking the address of an overloaded function, you need a target
type for the compiler to be able to work out which overload you are
referring to. You can specify the target type using an assignment or a
static_cast.

Tom
--
C++ FAQ: http://www.parashift.com/c++-faq-lite/
C FAQ: http://www.eskimo.com/~scs/C-faq/top.html

[tom_usenet]

On 7 Apr 2004 02:52:48 -0700, ma***********@v irgilio.it
(marco_segurini ) wrote:

Hi,

if I compile the following code I get the error:

RemoveIf.cpp(1 9) : error C2914: 'remove_if' : cannot deduce template
argument as function argument is ambiguous

#include <algorithm>
#include <vector>

template<typen ame T>
class vector_t
: public std::vector<T>
{
bool TestRemove(long Pos) const //(1)
{
return false;
}
static bool TestRemove(cons t T &) //(2)
{
return false;
}
public:
void RemoveIf()
{
bool (*remover)(cons t T&) = &vector_t<T>::T estRemove;
erase(std::remo ve_if(begin(), end(), remover),
end()); //this is line 19
How may I force the remove_if to use the TestRemove (2) function as
predicate?

Either the above, or add a static cast to select the function type:

erase(
std::remove_if(
begin(),
end(),
static_cast<boo l (*)(const T&)>(&vector_t< T>::TestRemove )
),
end()
);

When taking the address of an overloaded function, you need a target
type for the compiler to be able to work out which overload you are
referring to. You can specify the target type using an assignment or a
static_cast.

Tom
--
C++ FAQ: http://www.parashift.com/c++-faq-lite/
C FAQ: http://www.eskimo.com/~scs/C-faq/top.html