I have to convert an float number to int without using casting i= (int) f,
without printf and others. I can only use int, char and structs. Can anyone
help?
Thanks
Juerg
13  2718 
On Tue, 10 Feb 2004 17:07:56 +0100 in comp.lang.c++, "Link"
<ju********@lil asystem.ch> was alleged to have written: I have to convert an float number to int without using casting i= (int) f,
without printf and others. I can only use int, char and structs.
What is it about the standard built-in conversion from float to int
(what you call "casting") that makes it unsuitable for your application?
Anything else is doing it the hard way.
Link writes: I have to convert an float number to int without using casting i= (int) f,
without printf and others. I can only use int, char and structs. Can
anyone help?
I assume this is a student assignment. The first step is to find out how
your platform encodes a float. Look at the documentation that came with
your compiler. It is almost certain that an int is encoded as a two's
complement binary number and it's size will be in <limits.h>. Are you sure
that unions are forbidden? They might turn out to be handy, too.
Sounds like a fun and informative exercise.
Yes, I have it to do in the hard way - Its only a little box (not pc) and so
I can't use all libs (reduced memory, ...)
You know someting about working with exp, mantissa and so, only with int and
struct?
"David Harmon" <so****@netcom. com> schrieb im Newsbeitrag
news:40******** *******@news.we st.earthlink.ne t... On Tue, 10 Feb 2004 17:07:56 +0100 in comp.lang.c++, "Link"
<ju********@lil asystem.ch> was alleged to have written:I have to convert an float number to int without using casting i= (int)
f,without printf and others. I can only use int, char and structs.
What is it about the standard built-in conversion from float to int
(what you call "casting") that makes it unsuitable for your application?
Anything else is doing it the hard way.
Its a work on a little box with not much memory and I'm using borland turbo
compiler (TC)
typedef struct _MF {
unsigned long m : 23;
unsigned int e : 8;
unsigned int s : 1;
} MF;
union are ok.
You know more about working with mantissa, exponent and so?
"osmium" <r1********@com cast.net> schrieb im Newsbeitrag
news:c0******** *****@ID-179017.news.uni-berlin.de... Link writes:
I have to convert an float number to int without using casting i= (int)
f, without printf and others. I can only use int, char and structs. Can anyone help?
I assume this is a student assignment. The first step is to find out how
your platform encodes a float. Look at the documentation that came with
your compiler. It is almost certain that an int is encoded as a two's
complement binary number and it's size will be in <limits.h>. Are you
sure that unions are forbidden? They might turn out to be handy, too.
Sounds like a fun and informative exercise.
"Link" <ju********@lil asystem.ch> wrote... I have to convert an float number to int without using casting i= (int) f,
without printf and others. I can only use int, char and structs. Can
anyone help?
What is it, a well-camouflaged homework? Most processors that
can work with floating point numbers directly can load them into
their register as FP and store as an int. Two instructions, no
printf necessary. If you are so bound to a particular "box" as
you claim, use assembly language. Or does your processor lack
any support for floating-point numbers?
Link wrote: Its a work on a little box with not much memory and I'm using borland turbo
compiler (TC)
typedef struct _MF {
unsigned long m : 23;
unsigned int e : 8;
unsigned int s : 1;
} MF;
union are ok.
You know more about working with mantissa, exponent and so?
Well, you've virtually answered your question -
given that the floating point number is:
(s ? -1: 1 ) x m x 2^(e)
I think you can figure it out - however, be careful with 'e'. Is 'e'
really unsigned ? You also need to know what "m" is - is m really
normalized - meaning is the expression really :
(s ? -1: 1 ) x m x 2^(e-23)
Can you figure it out from there ?
On Tue, 10 Feb 2004 17:39:16 +0100 in comp.lang.c++, "Link"
<ju********@lil asystem.ch> was alleged to have written: Its a work on a little box with not much memory and I'm using borland turbo
compiler (TC)
Use the Borland assembly source out (the -S option if I recall) and
look at what it generates for the cast. Then consider whether you still
think you can do better. If you can, the assembly source will probably
give some clue as to which way to go.
As for comp.lang.c++, we do try to keep to standard portable stuff
here, so twiddling mantissas and such will not be too popular.
See the welcome message posted twice per week in comp.lang.c++ or
available at http://www.slack.net/~shiva/welcome.txt
"Victor Bazarov" <v.********@com Acast.net> wrote in message news:E58Wb.2718 79$xy6.1382070@ attbi_s02... "Link" <ju********@lil asystem.ch> wrote... I have to convert an float number to int without using casting i= (int) f,
without printf and others. I can only use int, char and structs. Can
anyone help?
What is it, a well-camouflaged homework? Most processors that
can work with floating point numbers directly can load them into
their register as FP and store as an int.
Too bad that doesn't include pentiums.
On Tue, 10 Feb 2004 14:21:37 -0500, "Ron Natalie" <ro*@sensor.com >
wrote:
"Victor Bazarov" <v.********@com Acast.net> wrote in message news:E58Wb.2718 79$xy6.1382070@ attbi_s02... "Link" <ju********@lil asystem.ch> wrote... > I have to convert an float number to int without using casting i= (int) f,
> without printf and others. I can only use int, char and structs. Can
anyone > help?
What is it, a well-camouflaged homework? Most processors that
can work with floating point numbers directly can load them into
their register as FP and store as an int.
Too bad that doesn't include pentiums.
It doesn't? FILD/FIST don't work? Bit on the slow side, but they
always worked for me..... This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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