ternary operator and ostreams

[Roger Leigh]

This code works (GCC 3.3.3):

#include <iostream>
int main()
{
bool a = true;
std::cout << "True and false\n"
<< (a == true) ? 't' : 'f';
std::cout << "\n";
return 0;
}

But this code does not:

#include <iostream>

int main()
{
bool a = true;

std::cout << "True and false\n"
<< (a == true) ? 't' : 'f'
<< "\n";

return 0;
}

test.cc: In function `int main()':
test.cc:9: error: invalid operands of types `char' and `const char[2]' to
binary `operator<<'

However, if I enclose the entire ternary expression in parentheses
"((a == true) ? 't' : 'f')" then it does compile.

What is different between these two forms? Both return a char, but
only the latter returns a std::ostream& when used in the above
expression.
Many thanks,
Roger

--
Roger Leigh

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[lilburne]

Roger Leigh wrote:

What is different between these two forms? Both return a char, but
only the latter returns a std::ostream& when used in the above
expression.

Check operator precedence:
(a == true) ? 't' : ('f' << "\n");

[Jerry Coffin]

In article <87************ @wrynose.whinla tter.uklinux.ne t>, ${roger}
@invalid.whinla tter.uklinux.ne t.invalid says...

This code works (GCC 3.3.3):
[ snipped ]
But this code does not:

#include <iostream>

int main()
{
bool a = true;

std::cout << "True and false\n"
<< (a == true) ? 't' : 'f'
<< "\n";

return 0;
}

This is a precedence problem -- the compiler is trying to treat this as:

(a==true)? 't' : ('f' << '\n');

I.e. trying to shift 'f' left by '\n' bits. This would actually work
(it would typically shift 'f' left by 13 bits) except for one minor
detail: the result of that bit-shift would be an int, and your other
result is 't' which is a char. The compiler does insist that both
results in a ?: be of the same type.

When '<<' is used in its traditional role (bit-shifting) it more or less
makes sense to be able to bit-shift an operand of ?: without extra
parentheses. When you're using it for I/O it usually makes less sense,
but the compiler always give the operand its original precedence and
associativity.

I'd also note that your '==true' is utterly vacuous and kind of stupid
when you think about it -- 'a' starts out as a bool, and your comparison
to true produces a bool that's always equal to a's original value.
Since a is a bool, just use it directly:

std::cout << (a ? 't' : 'f') << "\n";

If you're going to compare it to true, then you probably need to compare
the result of that comparison to true as well -- and so on indefinitely.

Also note that iostreams already support writing bools out in text
format, though they produce 'true' and 'false' instead of the 't' and
'f' you've used.

--
Later,
Jerry.

The universe is a figment of its own imagination.

[Roger Leigh]

lilburne <li******@godzi lla.com> writes:

Roger Leigh wrote:

What is different between these two forms? Both return a char, but
only the latter returns a std::ostream& when used in the above
expression.

Check operator precedence:
(a == true) ? 't' : ('f' << "\n");

Doh! How could I have been that unobservant?
Thanks,
Roger

--
Roger Leigh

Printing on GNU/Linux? http://gimp-print.sourceforge.net/
GPG Public Key: 0x25BFB848. Please sign and encrypt your mail.

[Roger Leigh]

Jerry Coffin <jc*****@taeus. com> writes:

In article <87************ @wrynose.whinla tter.uklinux.ne t>, ${roger}
@invalid.whinla tter.uklinux.ne t.invalid says...

This code works (GCC 3.3.3):
[ snipped ]

But this code does not:

#include <iostream>

int main()
{
bool a = true;

std::cout << "True and false\n"
<< (a == true) ? 't' : 'f'
<< "\n";

return 0;
}

I'd also note that your '==true' is utterly vacuous and kind of stupid
when you think about it -- 'a' starts out as a bool, and your comparison
to true produces a bool that's always equal to a's original value.
Since a is a bool, just use it directly:

std::cout << (a ? 't' : 'f') << "\n";
That's an excellent point, thanks!
Also note that iostreams already support writing bools out in text
format, though they produce 'true' and 'false' instead of the 't' and
'f' you've used.

That's probably even better. However, I'm constructing SQL database
queries with this, and I want to ensure the "true" and "false" will
never be localised. From what I've seen you need to manually add this
facility to a locale to get localised strings? I want to avoid this
ever occuring if possible.
--
Roger Leigh

Printing on GNU/Linux? http://gimp-print.sourceforge.net/
GPG Public Key: 0x25BFB848. Please sign and encrypt your mail.

[Jerry Coffin]

In article <87************ @wrynose.whinla tter.uklinux.ne t>, ${roger}
@invalid.whinla tter.uklinux.ne t.invalid says...

[ ... ]

Also note that iostreams already support writing bools out in text
format, though they produce 'true' and 'false' instead of the 't' and
'f' you've used.

That's probably even better. However, I'm constructing SQL database
queries with this, and I want to ensure the "true" and "false" will
never be localised. From what I've seen you need to manually add this
facility to a locale to get localised strings? I want to avoid this
ever occuring if possible.

The default global locale is the "C" locale, which will always spell
these as "true" and "false". If you change the global locale (e.g. with
setlocale) then you may have to explicitly imbue this stream with the
"C" locale again to get the desired behavior. Given that it's crucial
for it to use the "C" locale, you might want to imbue it explicitly even
if (for now) you're never changing locales at all. IIRC, one way to do
that should be something like this:

/* warning: untested code */
std::fstream SQL_stuff("file name.sql");

std::locale def_loc("C");
SQL_stuff.imbue (def_loc);

This way, if you add localization code in the future, you're still
assured that this stream will use the default locale.

--
Later,
Jerry.

The universe is a figment of its own imagination.

[Roger Leigh]

Jerry Coffin <jc*****@taeus. com> writes:

In article <87************ @wrynose.whinla tter.uklinux.ne t>, ${roger}
@invalid.whinla tter.uklinux.ne t.invalid says...

[ ... ]

> Also note that iostreams already support writing bools out in text
> format, though they produce 'true' and 'false' instead of the 't' and
> 'f' you've used.

That's probably even better. However, I'm constructing SQL database
queries with this, and I want to ensure the "true" and "false" will
never be localised. From what I've seen you need to manually add this
facility to a locale to get localised strings? I want to avoid this
ever occuring if possible.

The default global locale is the "C" locale, which will always spell
these as "true" and "false". If you change the global locale (e.g. with
setlocale) then you may have to explicitly imbue this stream with the
"C" locale again to get the desired behavior. Given that it's crucial
for it to use the "C" locale, you might want to imbue it explicitly even
if (for now) you're never changing locales at all. IIRC, one way to do
that should be something like this:

/* warning: untested code */
std::fstream SQL_stuff("file name.sql");

std::locale def_loc("C");
SQL_stuff.imbue (def_loc);

This way, if you add localization code in the future, you're still
assured that this stream will use the default locale.

Thanks for clearing that up. I'm currently using "C", and I've
explicitly selected "C" as the default locale, but I hope to
internationalis e it at some point in the near future (I need to clean
up some numeric formatting issues first). I just need to make sure
the communcation with the database (and other programs) is
standardised to use "C".

I'm using std::ostringstr eam to construct the queries, so it'll be no
big deal to explicitly imbue them with "C".
Many thanks for your help,
Roger

--
Roger Leigh

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