Dicitionary Geneic Class

[uday1302]

Hi All,
Can anyone help me out regarding Dicitonary Generic Class using c#.

Like I have 3 btns(add, edit and delete), text box , LisBox, Listview. If i add an item from Text it should be added to lIstbox and i have items in listview. They should be assigned to listbox selected item. these can be done through dicitonary classes. If i add new one Listbox item and new listview items are to be added to that selected item.

[mldisibio]

The ListBox displays a ListBox.ObjectCollection, which is simply a collection of objects.
The ListView contains a ListViewItemCollection which is a collection of ListViewItems.
A Dictionary has a collection of KeyValuePairs.

If you want the ListBox to somehow reflect the combination of the TextBox value and the ListView item, you might consider making the each ListBox item a KeyValuePair<string, ListViewItem>.

[uday1302]

I have Listbox(lstgroups) and listview(lstItems). say items in lisbox as Groups and in listview as Items.
Each Group should have list of items, when i add an new item to lstitems. it should assign to selected group.
By using dictionary classes
Here List<object> should return lstitems


Dictionary<string, List<object>> d= new Dictionary(string, List<object>>();

d.add(lstgroups.items, new List<object>);

//error cumes here, how to assign here List<>

[vekipeki]

Here is an example of using Dictionary<>: System.Collections.Generic.Dictionary.

Try to explain what is the goal you are trying to accomplish, maybe you don't need a dictionary?

If you want to assing a list of items to a "group", the easiest way would be to create that list first, and then add it to the dictionary:

// create a list
List<Object> someItems = new List<Object>;
 
// add some items
someItems.AddRange( /* add the items */);
 
// add these items with a specified key ("group name")
d.Add(groupName, someItems);
 

Note also:
1. you have to do this for each group
2. you cannot add the same groupName twice (it will raise an exception)

[mldisibio]

Small syntax note:

List<Object> someItems = new List<Object>();