SortedList<T> missing GetByIndex method?

[Bruce Wood]

SortedList<Tgeneric has most of the methods of the old SortedList
class, but it's missing a few, and one in particular that puzzles me.

Anyone know why it has no GetByIndex method?

It has IndexOfKey(), and IndexOfValue(), so you can ask it for indices
into the list. You just can't do anything with them, because it has no
method that takes an index and gives you back anything, neither an
entry, nor a key, nor a value.

The old SortedList would at least give you back the value given the
index.

So... what's the use of a sorted list if you can't get the n-th entry?

Was this an oversight? Or is it by design? Or am I blind...?

[Peter Duniho]

On Wed, 18 Jul 2007 16:32:41 -0700, Peter Duniho
<Np*********@nnowslpianmk.comwrote:

SortedList<intlistOfInts;

...
int i = listOfInts.Values[0];

And yes, my declaration of SortedList<is wrong (as is your reference to
the non-existent generic class "SortedList<T>"...it's actually
"SortedList<TKey, TValue>" :p )...one hopes that that does not in any way
impeded your ability to get the general idea of how to index into the
values of the generic sorted list. :)

[Chris Dunaway]

On Jul 18, 6:38 pm, "Peter Duniho" <[e-mail]>
wrote:

On Wed, 18 Jul 2007 16:32:41 -0700, Peter Duniho

<[e-mail]:

SortedList<intlistOfInts;

...
int i = listOfInts.Values[0];

And yes, my declaration of SortedList<is wrong (as is your reference to
the non-existent generic class "SortedList<T>"...it's actually
"SortedList<TKey, TValue>" :p )...one hopes that that does not in any way
impeded your ability to get the general idea of how to index into the
values of the generic sorted list. :)

If you use an integer as the key, you can use this syntax:

SortedList<int, stringlist = new SortedList<int, string>();

....

string s = list[4];

Chris