combine four bytes into an integer

[les]

If all are unsigned integers, then why not make it easy
on yourself and just multiply each by a scaler to effect
the shift? ie

each position is just multiplied by 128^n-1

byte1 + byte2*128 + byte3 *(128 *128) + byte4 * (128 *
128 *128)

-----Original Message-----
Hello everyone,

I have the following problem. Four sequential bytes represent a binarynumber, where the 7th bit is allways 0, so each of the bytes looks like0yyyyyyy. I cannot find a way to turn this binary number into an integer.Unfortunately all books I have on C# don't delve too deep into binaryarithmetics :(((

Could anyone help me with this please? TIA!

[Jon Skeet [C# MVP]]

les <mo****@dshs.wa.gov> wrote:

If all are unsigned integers, then why not make it easy
on yourself and just multiply each by a scaler to effect
the shift? ie

each position is just multiplied by 128^n-1

byte1 + byte2*128 + byte3 *(128 *128) + byte4 * (128 *
128 *128)

I don't know about anyone else, but I find that a lot less clear than
using the actual shift operator:

byte1 +
(byte2 << 7) +
(byte3 << 14) +
(byte4 << 21)

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet
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