Launching another form from current form

[Dan]

Hi. I'm trying to launch a second form from code in a first, but it doesn't
seem to working.

Originally I tried to write the code as follows (Form2 has a public method
called AttachDataSet):

Application.Run(new Form2());
Form2.AttachDataSet(ds);
Form2.Show();

However, Intellisense couldn't find the AttachDataSet method using that
code. So I changed it to:

Form2 fm2 = new Form2();
Application.Run(fm2);
fm2.AttachDataSet(ds);
fm2.Show();

But when the code runs, nothing seems to happen. Further, if I put a break
point at fm2.Show, I never get there.

Anybody know (a) what's going on in my current code, and (b) how to do what
I want?

Thanks...

Dan

[Miha Markic [MVP C#]]

Hi Dan,

Put the line AttachDataSet(ds); into Form2's constructor and change your
code to:

Form2 fm2 = new Form2();

Application.Run(fm2);
// fm2.Show(); don't need this

Call to Application.Run(fm2); won't return until frm2 is closed.

--
Miha Markic [MVP C#] - RightHand .NET consulting & software development
miha at rthand com
www.rthand.com

"Dan" <da*@dontspamme.com> wrote in message
news:%2****************@TK2MSFTNGP10.phx.gbl... Hi. I'm trying to launch a second form from code in a first, but it doesn't seem to working.

Originally I tried to write the code as follows (Form2 has a public method
called AttachDataSet):

Application.Run(new Form2());
Form2.AttachDataSet(ds);
Form2.Show();

However, Intellisense couldn't find the AttachDataSet method using that
code. So I changed it to:

Form2 fm2 = new Form2();
Application.Run(fm2);
fm2.AttachDataSet(ds);
fm2.Show();

But when the code runs, nothing seems to happen. Further, if I put a break point at fm2.Show, I never get there.

Anybody know (a) what's going on in my current code, and (b) how to do what I want?

Thanks...

Dan

[Dan]

Thanks Miha. If I wanted to launch the form and continuing executing (i.e.
launch the form non-modally), how would I do that?

"Miha Markic [MVP C#]" <miha at rthand com> wrote in message
news:eS**************@TK2MSFTNGP12.phx.gbl...

Hi Dan,

Put the line AttachDataSet(ds); into Form2's constructor and change your
code to:

Form2 fm2 = new Form2();

Application.Run(fm2);
// fm2.Show(); don't need this

Call to Application.Run(fm2); won't return until frm2 is closed.

--
Miha Markic [MVP C#] - RightHand .NET consulting & software development
miha at rthand com
www.rthand.com

"Dan" <da*@dontspamme.com> wrote in message
news:%2****************@TK2MSFTNGP10.phx.gbl...

Hi. I'm trying to launch a second form from code in a first, but it

doesn't

seem to working.

Originally I tried to write the code as follows (Form2 has a public method called AttachDataSet):

Application.Run(new Form2());
Form2.AttachDataSet(ds);
Form2.Show();

However, Intellisense couldn't find the AttachDataSet method using that
code. So I changed it to:

Form2 fm2 = new Form2();
Application.Run(fm2);
fm2.AttachDataSet(ds);
fm2.Show();

But when the code runs, nothing seems to happen. Further, if I put a

break

point at fm2.Show, I never get there.

Anybody know (a) what's going on in my current code, and (b) how to do

what

I want?

Thanks...

Dan

[Philip Rieck]

If you are already in a form's code (inside Form1.xxx()), then get rid of
the Application.Run(),
public void OpenForm()
{
Form2 fm2 = new Form2();
fm2.AttachDataSet(ds);
fm2.Show();
}
Application.Run should only show up once in your app - normally in your
"main".
"Dan" <da*@dontspamme.com> wrote in message
news:Oc**************@TK2MSFTNGP09.phx.gbl...

Thanks Miha. If I wanted to launch the form and continuing executing (i.e. launch the form non-modally), how would I do that?

"Miha Markic [MVP C#]" <miha at rthand com> wrote in message
news:eS**************@TK2MSFTNGP12.phx.gbl...

Hi Dan,

Put the line AttachDataSet(ds); into Form2's constructor and change your
code to:

Form2 fm2 = new Form2();

Application.Run(fm2);
// fm2.Show(); don't need this

Call to Application.Run(fm2); won't return until frm2 is closed.

--
Miha Markic [MVP C#] - RightHand .NET consulting & software development
miha at rthand com
www.rthand.com

"Dan" <da*@dontspamme.com> wrote in message
news:%2****************@TK2MSFTNGP10.phx.gbl...

Hi. I'm trying to launch a second form from code in a first, but it

doesn't

seem to working.

Originally I tried to write the code as follows (Form2 has a public method called AttachDataSet):

Application.Run(new Form2());
Form2.AttachDataSet(ds);
Form2.Show();

However, Intellisense couldn't find the AttachDataSet method using that code. So I changed it to:

Form2 fm2 = new Form2();
Application.Run(fm2);
fm2.AttachDataSet(ds);
fm2.Show();

But when the code runs, nothing seems to happen. Further, if I put a

break

point at fm2.Show, I never get there.

Anybody know (a) what's going on in my current code, and (b) how to do

what

I want?

Thanks...

Dan

[Miha Markic [MVP C#]]

Hi,

Philip is absolutely right - Application.Run is used for application to know
when it should close you application (when the form you pass is closed).

--
Miha Markic [MVP C#] - RightHand .NET consulting & software development
miha at rthand com
www.rthand.com

"Philip Rieck" <st***@mckraken.com> wrote in message
news:Ox**************@TK2MSFTNGP11.phx.gbl...

If you are already in a form's code (inside Form1.xxx()), then get rid of
the Application.Run(),
public void OpenForm()
{
Form2 fm2 = new Form2();
fm2.AttachDataSet(ds);
fm2.Show();
}
Application.Run should only show up once in your app - normally in your
"main".
"Dan" <da*@dontspamme.com> wrote in message
news:Oc**************@TK2MSFTNGP09.phx.gbl...

Thanks Miha. If I wanted to launch the form and continuing executing

(i.e.

launch the form non-modally), how would I do that?

"Miha Markic [MVP C#]" <miha at rthand com> wrote in message
news:eS**************@TK2MSFTNGP12.phx.gbl...

Hi Dan,

Put the line AttachDataSet(ds); into Form2's constructor and change your code to:

Form2 fm2 = new Form2();
> Application.Run(fm2);
> // fm2.Show(); don't need this
Call to Application.Run(fm2); won't return until frm2 is closed.

--
Miha Markic [MVP C#] - RightHand .NET consulting & software development miha at rthand com
www.rthand.com

"Dan" <da*@dontspamme.com> wrote in message
news:%2****************@TK2MSFTNGP10.phx.gbl...
> Hi. I'm trying to launch a second form from code in a first, but it
doesn't
> seem to working.
>
> Originally I tried to write the code as follows (Form2 has a public

method

> called AttachDataSet):
>
> Application.Run(new Form2());
> Form2.AttachDataSet(ds);
> Form2.Show();
>
> However, Intellisense couldn't find the AttachDataSet method using that > code. So I changed it to:
>
> Form2 fm2 = new Form2();
> Application.Run(fm2);
> fm2.AttachDataSet(ds);
> fm2.Show();
>
> But when the code runs, nothing seems to happen. Further, if I put a break
> point at fm2.Show, I never get there.
>
> Anybody know (a) what's going on in my current code, and (b) how to do what
> I want?
>
> Thanks...
>
> Dan
>
>

[Dan]

Thanks a lot guys.

"Miha Markic [MVP C#]" <miha at rthand com> wrote in message
news:O1**************@TK2MSFTNGP12.phx.gbl...

Hi,

Philip is absolutely right - Application.Run is used for application to know when it should close you application (when the form you pass is closed).

--
Miha Markic [MVP C#] - RightHand .NET consulting & software development
miha at rthand com
www.rthand.com

"Philip Rieck" <st***@mckraken.com> wrote in message
news:Ox**************@TK2MSFTNGP11.phx.gbl...

If you are already in a form's code (inside Form1.xxx()), then get rid of

the Application.Run(),
public void OpenForm()
{
Form2 fm2 = new Form2();
fm2.AttachDataSet(ds);
fm2.Show();
}
Application.Run should only show up once in your app - normally in your
"main".
"Dan" <da*@dontspamme.com> wrote in message
news:Oc**************@TK2MSFTNGP09.phx.gbl...

Thanks Miha. If I wanted to launch the form and continuing executing (i.e.

launch the form non-modally), how would I do that?

"Miha Markic [MVP C#]" <miha at rthand com> wrote in message
news:eS**************@TK2MSFTNGP12.phx.gbl...
> Hi Dan,
>
> Put the line AttachDataSet(ds); into Form2's constructor and change

your > code to:
>
> Form2 fm2 = new Form2();
> > Application.Run(fm2);
> > // fm2.Show(); don't need this
>
>
> Call to Application.Run(fm2); won't return until frm2 is closed.
>
> --
> Miha Markic [MVP C#] - RightHand .NET consulting & software development > miha at rthand com
> www.rthand.com
>
> "Dan" <da*@dontspamme.com> wrote in message
> news:%2****************@TK2MSFTNGP10.phx.gbl...
> > Hi. I'm trying to launch a second form from code in a first, but it > doesn't
> > seem to working.
> >
> > Originally I tried to write the code as follows (Form2 has a public method
> > called AttachDataSet):
> >
> > Application.Run(new Form2());
> > Form2.AttachDataSet(ds);
> > Form2.Show();
> >
> > However, Intellisense couldn't find the AttachDataSet method using

that

> > code. So I changed it to:
> >
> > Form2 fm2 = new Form2();
> > Application.Run(fm2);
> > fm2.AttachDataSet(ds);
> > fm2.Show();
> >
> > But when the code runs, nothing seems to happen. Further, if I

put a > break
> > point at fm2.Show, I never get there.
> >
> > Anybody know (a) what's going on in my current code, and (b) how

to

do > what
> > I want?
> >
> > Thanks...
> >
> > Dan
> >
> >
>
>