How do I read values from XmlEnumAttribut e values of an Enum

[fahad77]

I created a class out of .xsd. Now I am generating a new xml file and trying to add "Notice" as an element with an attribute of Index="001". I'm trying to get to value XmlEnumAttribut e("0001"). This is how my code looks like:
*************** **********Class *************** *************** ***
public partial class Notice {

private NoticeIndex indexField;

public Notice() {
this.indexField = NoticeIndex.Ite m0001;
}

/// <remarks/>
[System.Xml.Seri alization.XmlAt tributeAttribut e()]
[System.Componen tModel.DefaultV alueAttribute(
NoticeIndex.Ite m0001)]
public NoticeIndex Index {
get {
return this.indexField ;
}
set {
this.indexField = value;
}
}

/// <remarks/>
[System.CodeDom. Compiler.Genera tedCodeAttribut e("xsd", "2.0.50727.1432 ")]
[System.Serializ ableAttribute()]
[System.Xml.Seri alization.XmlTy peAttribute(Ano nymousType=true )]
public enum NoticeIndex {

/// <remarks/>
[System.Xml.Seri alization.XmlEn umAttribute("00 01")]
Item0001,
}
*************** **********End Class********** *************** ********
I saw another post here and tried this from my program but it complains about converting Index to string:
*************** ************Pro gram*********** *************** ********
Notice notice = new Notice();
Type enumType = typeof(NoticeIn dex);
foreach (System.Reflect ion.FieldInfo fi in enumType.GetFie lds())
{
object[] attrs = fi.GetCustomAtt ributes(typeof( XmlEnumAttribut e), false);
if (attrs.Length > 0)
{
bSNShipNotice.I ndex = ((XmlEnumAttrib ute)attrs[0]).Name;
}
}

xml.Element.Not ice = notice;
*************** *************** *************** *************** *********
Any help would be greatly appreciated.

[vekipeki]

If I understood what you're asking, your problem is that your Index property does not get serialized. The problem is that XmlSerializer does not serialize properties when their value is equal to their default value.

To resolve this, you can comment out the "DefaultVal ue" attributes for your properties:

// [System.ComponentModel.DefaultValueAttribute(NoticeIndex.Item0001)]
 

If xsd is generating your class at build time (on every build), you can also remove the 'default' attribute from your Notice element xsd schema to avoid getting the DefaultValueAtt ribute in code, but if you cannot change the schema and need to have it updated on every build, consider adding an additional build script to comment out those lines for you (at Perl or batch file, or even a small C# console app, just to be sure that you don't forget it).

[fahad77]

Thanks for the help vekipeki, it actually works after I comment out the default attribute value and i'm not generating a class out of xsd on a runtime, its just one time thing so I guess i will be okay.