serializing List<List<strin g>>

[parez]

Hi,

I am trying to serialize List<List<strin g>.

With the following code

[XmlArrayItem("D ataRow")]
[XmlArray("DataR ows")]
public List<List<strin g>DataRows { get; set; }
I get the following

<DataRows>
<DataRow>
<string>123</string>
<string>432</string>
<string>423</string>
</DataRow>
<DataRow>
<string>4543</string>
<string>53</string>
<string>533</string>
</DataRow>
</DataRows>
I want the output to have <DataRowItemins tead of <string>.

One way it mite work is
if I "box" List<stringas SomeList and then have List<SomeList>. .But
there should be an easier way.

TIA

[parez]

On Apr 22, 11:22 am, parez <psaw...@gmail. comwrote:

Hi,

I am trying to serialize List<List<strin g>.

With the following code

[XmlArrayItem("D ataRow")]
[XmlArray("DataR ows")]
public List<List<strin g>DataRows { get; set; }

I get the following

<DataRows>
<DataRow>
<string>123</string>
<string>432</string>
<string>423</string>
</DataRow>
<DataRow>
<string>4543</string>
<string>53</string>
<string>533</string>
</DataRow>
</DataRows>

I want the output to have <DataRowItemins tead of <string>.

One way it mite work is
if I "box" List<stringas SomeList and then have List<SomeList>. .But
there should be an easier way.

TIA

That didnt work...
I tried
[XmlArrayItem("D ataRow",typeof( Datarow))]
[XmlArray("DataR ows")]
public List<DatarowDat aRows { get; set; }


public class Datarow
{
public Datarow()
{
DataRow = new List<string>();
}
[XmlArrayItem("D ataRowItems")]

public List<stringData Row { get; set; }
}

and this is what i got..

<DataRows>
<DataRow>
<DataRow>
<DataRowItems>1 23</DataRowItems>
<DataRowItems>4 32</DataRowItems>
<DataRowItems>4 23</DataRowItems>
</DataRow>
</DataRow>
<DataRow>
<DataRow>
<DataRowItems>4 543</DataRowItems>
<DataRowItems>5 3</DataRowItems>
<DataRowItems>5 33</DataRowItems>
</DataRow>
</DataRow>
</DataRows>

any one..

[parez]

On Apr 22, 1:12 pm, parez <psaw...@gmail. comwrote:

On Apr 22, 11:22 am, parez <psaw...@gmail. comwrote:

Hi,

I am trying to serialize List<List<strin g>.

With the following code

[XmlArrayItem("D ataRow")]
[XmlArray("DataR ows")]
public List<List<strin g>DataRows { get; set; }

I get the following

<DataRows>
<DataRow>
<string>123</string>
<string>432</string>
<string>423</string>
</DataRow>
<DataRow>
<string>4543</string>
<string>53</string>
<string>533</string>
</DataRow>
</DataRows>

I want the output to have <DataRowItemins tead of <string>.

One way it mite work is
if I "box" List<stringas SomeList and then have List<SomeList>. .But
there should be an easier way.

TIA

That didnt work...

I tried
[XmlArrayItem("D ataRow",typeof( Datarow))]
[XmlArray("DataR ows")]
public List<DatarowDat aRows { get; set; }

public class Datarow
{
public Datarow()
{
DataRow = new List<string>();
}
[XmlArrayItem("D ataRowItems")]

public List<stringData Row { get; set; }
}

and this is what i got..

<DataRows>
<DataRow>
<DataRow>
<DataRowItems>1 23</DataRowItems>
<DataRowItems>4 32</DataRowItems>
<DataRowItems>4 23</DataRowItems>
</DataRow>
</DataRow>
<DataRow>
<DataRow>
<DataRowItems>4 543</DataRowItems>
<DataRowItems>5 3</DataRowItems>
<DataRowItems>5 33</DataRowItems>
</DataRow>
</DataRow>
</DataRows>

any one..

Any body.. somebody..

[Peter Duniho]

On Tue, 22 Apr 2008 15:15:20 -0700, parez <ps*****@gmail. comwrote:

[...]
Any body.. somebody..

For what it's worth, 3 hours since the last post isn't really enough time
for there to be any sense in being impatient.

As for the actual question, I'm no expert in serialization, but it may be
that you simply can't do what you want using only the XmlSerializatio n
attributes. If not, it is actually not that hard to implement
ISerializable so that you have more control over the output.

One possible option would be to make your collection a
List<List<DataR owItem>>, using the default behavior for that property, but
implementing ISerializable on the (newly defined) DataRowItem class such
that it will serialize as "<DataRowItem>x xxx</DataRowItem>".

Pete

[parez]

On Apr 22, 6:47 pm, "Peter Duniho" <NpOeStPe...@nn owslpianmk.com>
wrote:

On Tue, 22 Apr 2008 15:15:20 -0700, parez <psaw...@gmail. comwrote:

[...]
Any body.. somebody..

For what it's worth, 3 hours since the last post isn't really enough time
for there to be any sense in being impatient.

As for the actual question, I'm no expert in serialization, but it may be
that you simply can't do what you want using only the XmlSerializatio n
attributes. If not, it is actually not that hard to implement
ISerializable so that you have more control over the output.

One possible option would be to make your collection a
List<List<DataR owItem>>, using the default behavior for that property, but
implementing ISerializable on the (newly defined) DataRowItem class such
that it will serialize as "<DataRowItem>x xxx</DataRowItem>".

Pete

Thanks..

i gave up on it..

i am going to go with

<DataRows>
<DataRow>
<string>123</string>
<string>432</string>
<string>423</string>
</DataRow>
<DataRow>
<string>4543</string>
<string>53</string>
<string>533</string>
</DataRow>
</DataRows>

I am going to ask the server guys to change the xml... they owe me
one.. actually a lot...