Hi All,
I saw my code jump out the function call directly without throw a
boundary error....
no boundary check ?
string[] str_member_id = new string[100];
str_member_id[id_count] = "sth"; // exit directly without throw a msg
when id_cound=101;
Best regards,
Boki.
3  1766 
Boki <bo******@ms21. hinet.netwrote:
I saw my code jump out the function call directly without throw a
boundary error....
no boundary check ?
string[] str_member_id = new string[100];
str_member_id[id_count] = "sth"; // exit directly without throw a msg
when id_cound=101;
No, it will be throwing an IndexOutOfRange Exception. If you have some
reason to believe this isn't happening, please post some code which
demonstrates it.
--
Jon Skeet - <sk***@pobox.co m> http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too
On Jul 1, 6:23 am, Jon Skeet [C# MVP] <s...@pobox.com wrote:
Boki <bokit...@ms21. hinet.netwrote:
I saw my code jump out the function call directly without throw a
boundary error....
no boundary check ?
string[] str_member_id = new string[100];
str_member_id[id_count] = "sth"; // exit directly without throw a msg
when id_cound=101;
No, it will be throwing an IndexOutOfRange Exception. If you have some
reason to believe this isn't happening, please post some code which
demonstrates it.
--
Jon Skeet - <s...@pobox.com >http://www.pobox.com/~skeet Blog:http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too
No, I didn't catch it. just assume code will stop and let me know it.
Thanks.
Boki.
Boki wrote:
>[...]
No, I didn't catch it. just assume code will stop and let me know it.
Thanks.
Perhaps you've run your application outside without your debugger or
started a release build ?
Boki.
Andre This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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