Getting single treeview node by path

[Christian Rühl]

heyho, guys! here's another question for you now:

i built an iterator to get all the nodes with a certain attribute in an

xml dom. it all looks like this (i'm using .NET framework 1.1)
string xpath;
// iterate over all xmlnodes with attribute "status='checke d'"
XPathDocument xpathDoc = new XPathDocument(m _configFile);
XPathNavigator xpathNav = xpathDoc.Create Navigator();
XPathNodeIterat or nodeIter = xpathNav.Select (@"/*[@status='checke d']");

while(nodeIter. MoveNext())
{
xpath = nodeIter.Curren tPosition.ToStr ing();
// here i want to address an treeview node with the xpath to
set its
checkbox

}
so what i want to know is: how can i address a treeview node by it's
path? for if i go like
treeView1.Selec tedNode.blabla it randomly choses a node in treeView
control.

[Christian Rühl]

Solution found:

string xpath = null;
XmlNode configNode = configDom.Docum entElement;
// collect selected nodes in node list
XmlNodeList nodeList =
configNode.Sele ctNodes(@"//*[@status='checke d']");

//MessageBox.Show (Convert.ToStri ng(nodeList.Cou nt));

// loop through nodelist
foreach(XmlNode myNode in nodeList)
{
xpath = GetPathFromNode (myNode); // get node path
xpath = xpath + "\\" + myNode.InnerTex t.ToString(); // complete path
string
}

[Christian Rühl]

oh, and of course the following:

//Loop through the Parent Nodes
for(int k=0; k<treeView1.Nod es.Count; k++)
{
root = treeView1.Nodes[k]; // parent node

if(("\\"+root.F ullPath.ToStrin g()) == xpath) // compare paths
root.Checked=tr ue; // set checkbox if node is found in tree view

// loop childs of root
for (int i=0; i<root.Nodes.Co unt; i++)
VisitChildNodes (root.Nodes[i], xpath);
}