Faster way to fill a byte array

[D. Yates]

All,

Is there a faster way to do this in C#:

byte[] buffer;
buffer = new byte[43];

for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;
Dave

[Jon Skeet [C# MVP]]

D. Yates <fo****@hotmail .com> wrote:

All,

Is there a faster way to do this in C#:

byte[] buffer;
buffer = new byte[43];

for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;

Yes:

byte[] buffer = new byte[43];

It's guaranteed to be all zeroes to start with.

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too

[Nicholas Paldino [.NET/C# MVP]]

Dave,

Yes:

byte[] buffer;
buffer = new byte[43];

By default, elements of arrays of structures are the same as those
structures with the bits zeroed out, which is exactly what you want.

Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m

"D. Yates" <fo****@hotmail .com> wrote in message
news:e$******** ******@TK2MSFTN GP14.phx.gbl...

All,

Is there a faster way to do this in C#:

byte[] buffer;
buffer = new byte[43];

for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;
Dave

[Francois Beaussier]

Hello,

If you just want a 0 initialized array, you don't have to use any for loop
as the .net framework already make sure that every single value in your
array is 0.

if you want to initialize to some other values than 0, you can do the
following :

byte[] aoe = new byte[] {4, 5, 3, 0, 0, 0, 2, 2};

--
Francois Beaussier

"D. Yates" <fo****@hotmail .com> a écrit dans le message de news:
e$************* *@TK2MSFTNGP14. phx.gbl...

All,

Is there a faster way to do this in C#:

byte[] buffer;
buffer = new byte[43];

for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;
Dave

[D. Yates]

Jon,

Assuming the byte array is being reused often, I was looking for a faster
way of doing this:

for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;

Dave

"Jon Skeet [C# MVP]" <sk***@pobox.co m> wrote in message
news:MP******** *************** *@msnews.micros oft.com...

D. Yates <fo****@hotmail .com> wrote:

All,

Is there a faster way to do this in C#:

byte[] buffer;
buffer = new byte[43];

for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;

Yes:

byte[] buffer = new byte[43];

It's guaranteed to be all zeroes to start with.

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too

[Brant Estes]

byte[] buffer;
// array is used, values set, etc.
Array.Clear(buf fer, 0, buffer.Length);
// array is now set to all zeros (or default values of whatever type
the array is)

[Nicholas Paldino [.NET/C# MVP]]

Dave,

You might get faster performance by passing the array to the static
Initialize method on the Array class.

However, the question has to be asked, why not just create a new array
when needed? If you are worried about memory concerns, that's what the GC
is for.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m

"D. Yates" <fo****@hotmail .com> wrote in message
news:%2******** ********@TK2MSF TNGP11.phx.gbl. ..

Jon,

Assuming the byte array is being reused often, I was looking for a faster
way of doing this:

for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;

Dave

"Jon Skeet [C# MVP]" <sk***@pobox.co m> wrote in message
news:MP******** *************** *@msnews.micros oft.com...

D. Yates <fo****@hotmail .com> wrote:

All,

Is there a faster way to do this in C#:

byte[] buffer;
buffer = new byte[43];

for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;

Yes:

byte[] buffer = new byte[43];

It's guaranteed to be all zeroes to start with.

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too

[D. Yates]

Brant,

Thanks, that's what I was looking for. The funny thing is that the Dev
Partner profiler states that my brute force method of clearing an array of
18 bytes was faster than calling the Array.Clear method.

Thanks again,
Dave

[Brant Estes]

Actually, now that I think of it, just simply reinitializing the array
does the same thing, and a little more than twice as performant:

byte[] buffer = new byte[] {1,2,3,4,5,6,7, 8,9};
buffer = new byte[buffer.Length];

[D. Yates]

Nicholas,

However, the question has to be asked, why not just create a new array
when needed? If you are worried about memory concerns, that's what the GC
is for.

Well, I'm trying to make a method that is called a lot more efficient. I
came up with three version:

Version 1:
public static void StringToFixedSi zeByteArray(str ing sValue, byte[]
buffer)
{
if (buffer != null)
{
if ((sValue != null) && (sValue.Length > 0))
{
for(int i = 0; i < buffer.Length; i++)
{
if (i < sValue.Length)
buffer[i] = (byte) sValue[i];
else buffer[i] = 0;
}
}
else
{
Array.Clear(buf fer, 0, buffer.Length);
// for(int i = 0; i < buffer.Length; i++)
// buffer[i] = 0;
}
}
}

and finally:

Version 2:
public static byte[] StringToFixedSi zeByteArray(str ing sValue, int
iFixedSize)
{
byte[] buffer;

if (iFixedSize > 0)
{
buffer = new byte[iFixedSize];
if ((sValue != null) && (sValue.Length > 0))
{
if (sValue.Length < iFixedSize)
System.Text.Enc oding.UTF8.GetB ytes(
sValue, 0, sValue.Length, buffer, 0);
else System.Text.Enc oding.UTF8.GetB ytes(
sValue, 0, iFixedSize, buffer, 0);
}
}
else buffer = null;

return buffer;
}
Version 3:
public static byte[] StringToFixedSi zeByteArray(str ing sValue, int
iFixedSize)
{
byte[] buffer;

if (iFixedSize > 0)
{
buffer = new byte[iFixedSize];
if ((sValue != null) && (sValue.Length > 0))
{
for(int i = 0; i < buffer.Length; i++)
{
if (i < sValue.Length)
buffer[i] = (byte) sValue[i];
else break;
}
}
}
else buffer = null;

return buffer;
}
Version 3 is the fastest; however, I think I'm going to go with Version 2.
Dave