Hi everybody
I have two treeviews, one of them is only to receive items dragged from
the treeview1. I want to know how to drag a full node information to
the treeview2. I know how to do that only in a single node operation.
Here is my current code:
private void trv_Directories _ItemDrag(objec t sender, ItemDragEventAr gs
e)
{
string strItem = e.Item.ToString ();
// Start the Drag Operation
DoDragDrop(strI tem, DragDropEffects .Copy);
}
private void trv_Directories _DragEnter(obje ct sender, DragEventArgs e)
{
// Determine if we are dragging something, if we are, set the effect
if (e.Data.GetData Present(DataFor mats.Text))
e.Effect = DragDropEffects .Copy;
else
e.Effect = DragDropEffects .None;
}
private void trv_Selection_D ragEnter(object sender, DragEventArgs e)
{
// Handle the Drag effect when the listbox is entered
if (e.Data.GetData Present(DataFor mats.Text))
e.Effect = DragDropEffects .Copy;
else
e.Effect = DragDropEffects .None;
}
private void trv_Selection_D ragDrop(object sender, DragEventArgs e)
{
string dummy = "";
bool itemFound = false;
// Get the string from the data that was dragged
string s = (string)e.Data. GetData(dummy.G etType());
s = s.Substring(s.I ndexOf(":") + 1).Trim();
Position.X = e.X;
Position.Y = e.Y;
Position = trv_Selection.P ointToClient(Po sition);
// Checks if the item to be dropped is new for the list
for(int i=0; i<trv_Selection .Nodes.Count; i++)
{
// If finds the item on the list don't do nothing
if(trv_Selectio n.Nodes[i].Text == s)
{
itemFound = true;
break;
}
else
itemFound = false;
}
// If the item wasn't found on the list, add it.
if(!itemFound)
// Drop the string in the listbox
trv_Selection.N odes.Add(s);
}
Any information will be appreciated!
Thanks!
Eduardo 1 3496 http://www.eggheadcafe.com/articles/...atabinding.asp
Learn an additional method for databinding a DataSet to a windows forms .NET
TreeView control. Learn how to drag and drop nodes on the same TreeView
control as well as drag and drop nodes across multiple TreeView controls
while maintaining the data bound relationship with the source and target
TreeView's DataSet.
--
Robbe Morris - 2004/2005 Microsoft MVP C# http://www.masterado.net
<em*******@gmai l.com> wrote in message
news:11******** **************@ o13g2000cwo.goo glegroups.com.. . Hi everybody
I have two treeviews, one of them is only to receive items dragged from the treeview1. I want to know how to drag a full node information to the treeview2. I know how to do that only in a single node operation.
Here is my current code:
private void trv_Directories _ItemDrag(objec t sender, ItemDragEventAr gs e) { string strItem = e.Item.ToString ();
// Start the Drag Operation DoDragDrop(strI tem, DragDropEffects .Copy); }
private void trv_Directories _DragEnter(obje ct sender, DragEventArgs e) { // Determine if we are dragging something, if we are, set the effect if (e.Data.GetData Present(DataFor mats.Text)) e.Effect = DragDropEffects .Copy; else e.Effect = DragDropEffects .None; }
private void trv_Selection_D ragEnter(object sender, DragEventArgs e) { // Handle the Drag effect when the listbox is entered if (e.Data.GetData Present(DataFor mats.Text)) e.Effect = DragDropEffects .Copy; else e.Effect = DragDropEffects .None; }
private void trv_Selection_D ragDrop(object sender, DragEventArgs e) { string dummy = ""; bool itemFound = false;
// Get the string from the data that was dragged string s = (string)e.Data. GetData(dummy.G etType()); s = s.Substring(s.I ndexOf(":") + 1).Trim(); Position.X = e.X; Position.Y = e.Y;
Position = trv_Selection.P ointToClient(Po sition);
// Checks if the item to be dropped is new for the list for(int i=0; i<trv_Selection .Nodes.Count; i++) { // If finds the item on the list don't do nothing if(trv_Selectio n.Nodes[i].Text == s) { itemFound = true; break; } else itemFound = false; }
// If the item wasn't found on the list, add it. if(!itemFound) // Drop the string in the listbox trv_Selection.N odes.Add(s); }
Any information will be appreciated!
Thanks!
Eduardo This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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--
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Gurudev
Software Engineer, NetKraft,
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