Hi,
I have a string which represent a date as follow: "dd-.MM-.yyyy hh:mm".
How could I convert this string to DateTime type (I prefer somehow to
set this as a pattern if it is possible because I have other
possibilities as "dd~MM~yyyy , hh:mm")?
Thanks. 9 2483
string myString = "1-1-2000";
DateTime myDateTime = DateTime.Parse( myString);
Hope this helps,
Arjen
"Iwan Petrow" <xx****@abv.b g> schreef in bericht
news:11******** **************@ o13g2000cwo.goo glegroups.com.. . Hi,
I have a string which represent a date as follow: "dd-.MM-.yyyy hh:mm". How could I convert this string to DateTime type (I prefer somehow to set this as a pattern if it is possible because I have other possibilities as "dd~MM~yyyy , hh:mm")?
Thanks.
"Iwan Petrow" <xx****@abv.b g> wrote in message
news:11******** **************@ o13g2000cwo.goo glegroups.com.. . I have a string which represent a date as follow: "dd-.MM-.yyyy hh:mm". How could I convert this string to DateTime type (I prefer somehow to set this as a pattern if it is possible because I have other possibilities as "dd~MM~yyyy , hh:mm")?
DateTime.Parse( ...)
Thanks.
But I want culture invariant.
I've found a class DateTimeFormatI nfo which is good enough but I want
to forbid AM and PM. I use HH but it doesn't work (it accepts them).
Any ideas for forbidding them (AM and PM)?
Hi,
One of the overloads of DateTime.ParseE xact does it:
DateTime.ParseE xact( "31-.12-.2005 23:51", "dd-.MM-.yyyy hh-.mm" ,
DateTimeFormatI nfo.InvariantIn fo );
Note:
I wrote the above line from memory, it may have some error in the format,
check it first, also note that the casing is important MM=month and
mm=minutes
Cheers,
--
Ignacio Machin,
ignacio.machin AT dot.state.fl.us
Florida Department Of Transportation
"Iwan Petrow" <xx****@abv.b g> wrote in message
news:11******** **************@ o13g2000cwo.goo glegroups.com.. . Hi,
I have a string which represent a date as follow: "dd-.MM-.yyyy hh:mm". How could I convert this string to DateTime type (I prefer somehow to set this as a pattern if it is possible because I have other possibilities as "dd~MM~yyyy , hh:mm")?
Thanks.
Iwan Petrow <xx****@abv.b g> wrote: But I want culture invariant.
In that case, pass the invariant culture into DateTime.ParseE xact.
I've found a class DateTimeFormatI nfo which is good enough but I want to forbid AM and PM. I use HH but it doesn't work (it accepts them).
Any ideas for forbidding them (AM and PM)?
Have you tried using ParseExact rather than just Parse?
--
Jon Skeet - <sk***@pobox.co m> http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
Thanks
It works in most cases. But for this there is a problem:
DateTime.ParseE xact( "31\\12\\20 05", "dd\\MM\\yy yy" ,
DateTimeFormatI nfo.InvariantIn *fo );
It throws exception with message "string is not a date" or something
similar.
Why? Any solutions?
Hi,
haa , tricky one :) , but easy to explain
if you look the help of DateTimeFormatI nfo you will see at the botton that
there is a \c variant :
\ c Where c is any character. Displays the character
literally. To display the backslash character, use "\\".
So, if you change the expression to:
DateTime d = DateTime.ParseE xact( @"31\12\2005 ", @"dd\\MM\\yy yy" ,
DateTimeFormatI nfo.InvariantIn fo );
you will be ok, see that I use the @ at the start, IMO it's clearer that
using two \
cheers,
--
Ignacio Machin,
ignacio.machin AT dot.state.fl.us
Florida Department Of Transportation
"Iwan Petrow" <xx****@abv.b g> wrote in message
news:11******** *************@g 14g2000cwa.goog legroups.com...
Thanks
It works in most cases. But for this there is a problem:
DateTime.ParseE xact( "31\\12\\20 05", "dd\\MM\\yy yy" ,
DateTimeFormatI nfo.InvariantIn fo );
It throws exception with message "string is not a date" or something
similar.
Why? Any solutions? This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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