Collection and struct address

[PauloFor]

Hi have :

struct A
{
public int val;
}

class OtherClass
{
private lis = new ArrayList();
public void Add(ref A element)
{
lis.Add(element );
}

public void SumAll(int num)
{
for (int i=0;i<lis.Count ;i++)
{
A work = (A) lis[i]t;
work.val += num;
lis[i] = work;
}
}

}

in code :

A test1 = new A();
A test2 = new A();

test1.val = 5;
test2.val = 7;
OtherClass.Add( ref test1);
OtherClass.Add( ref test2);
OtherClass.SumA ll(10);

here I want :
test1.val = 15 and test1.val = 17;

but I get :
test1.val = 5 and test2.val = 7;

What kind of collection is rigth for this ?
thks,
Paulo.

[Mattias Sjögren]

What kind of collection is rigth for this ?

No other collection will give you that behavior. You would have to
make A a class to make it work that way. When A is a struct you always
end upp passing copies of the data around (even if you use ref
parameters) and changing one copy does not affect others.

Mattias

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[Jon Skeet [C# MVP]]

Mattias Sjögren <ma************ ********@mvps.o rg> wrote:

What kind of collection is rigth for this ?

No other collection will give you that behavior. You would have to
make A a class to make it work that way. When A is a struct you always
end upp passing copies of the data around (even if you use ref
parameters) and changing one copy does not affect others.

Hang on - you *don't* always end up passing copies of the data around.
The call which passes the struct by reference doesn't make a copy of
the data. However, passing by reference can never let the called method
*store* a reference to the original variable anywhere, so after the Add
method has finished, the variable is "independen t" again.

--
Jon Skeet - <sk***@pobox.co m>
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[Mattias Sjögren]

Hang on - you *don't* always end up passing copies of the data around.

Oops, right, I didn't mean to say that, but I realize that I just did.
:-) Thanks for catching that. What I meant to say was that the
collection will store a (boxed) copy, whether or not the Add method
parameter is ref.

Mattias

--
Mattias Sjögren [MVP] mattias @ mvps.org
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