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DataView / DataRow

'ello

How can I get the DataRow of the DataGrid's SelectedItem for the bound
DataView's DataTable?

Thanx
Hein
Nov 15 '05 #1
4 13158
Hein,

DataRow dr =
((DataRowView)B indingContext[MyDataGrid.Data Source].Current).Row;

---
Steven Wood

"Hein Albrecht" <he***@magnumsi mplex.com> wrote in message
news:%2******** ********@TK2MSF TNGP11.phx.gbl. ..
'ello

How can I get the DataRow of the DataGrid's SelectedItem for the bound
DataView's DataTable?

Thanx
Hein

Nov 15 '05 #2
Hello,

First, obtain the corresponding CurrencyManager instance like this:

CurrencyManager cm =
(CurrencyManage r)theForm.Bindi ngContext[theGrid.DataSou rce,
theGrid.DataMem ber];

next, obtain the data view:

DataView theView = (DataView)cm.Li st;

and finally, get the row:

DataRow row = theView[cm.Current].Row;

--
Dmitriy Lapshin [C# / .NET MVP]
X-Unity Test Studio
http://x-unity.miik.com.ua/teststudio.aspx
Bring the power of unit testing to VS .NET IDE

"Hein Albrecht" <he***@magnumsi mplex.com> wrote in message
news:%2******** ********@TK2MSF TNGP11.phx.gbl. ..
'ello

How can I get the DataRow of the DataGrid's SelectedItem for the bound
DataView's DataTable?

Thanx
Hein


Nov 15 '05 #3
'ello

Thanx for the replies, but I seemed to forget to mention one thing. My

application uses C# webforms, so I can't use
System.Windows. Forms.BindingCo ntext.

Any other suggestions?

Thanx

Hein

"Steven Wood" <st*********@ho tmail.com> wrote in message
news:u0******** ******@TK2MSFTN GP10.phx.gbl...
Hein,

DataRow dr =
((DataRowView)B indingContext[MyDataGrid.Data Source].Current).Row;

---
Steven Wood

"Hein Albrecht" <he***@magnumsi mplex.com> wrote in message
news:%2******** ********@TK2MSF TNGP11.phx.gbl. ..
'ello

How can I get the DataRow of the DataGrid's SelectedItem for the bound
DataView's DataTable?

Thanx
Hein


Nov 15 '05 #4
Hein,
Thanx for the replies, but I seemed to forget to mention one thing. My
application uses C# webforms, so I can't use
System.Windows. Forms.BindingCo ntext.


I can think of two possible ways.

First, a DataGrid:

<ASP:DATAGRID id="myDataGrid " runat="server"
onitemcommand=" myDataGrid_Item Command">
<COLUMNS>
<ASP:BUTTONCOLU MN HeaderText="Sel ect Row"
ButtontType="Pu shButton"
Text="Select"
CommandName="Se lectRow">
</ASP:BUTTONCOLUM N>
<ASP:BOUNDCOLUM N HeaderText="MyI D" datafield="MyID ">
</ASP:BOUNDCOLUMN >
</COLUMNS>
</ASP:DATAGRID>

Then in your code behind file either:

1. Store the DataSet for the Grid in Session State (depending on its size)
and:

protected void myDataGrid_Item Command(object source,
System.Web.UI.W ebControls.Data GridCommandEven tArgs e)
{
TableCell myID = e.Item.Cells[1];
string key = myID.Text;
DataRow[] dr =
((DataSet)Sessi on["MyDataSet"]).Tables[0].Select("MyID=" + key);
}

or

(2) go back to the database with the id and get the single record:

protected void myDataGrid_Item Command(object source,
System.Web.UI.W ebControls.Data GridCommandEven tArgs e)
{
TableCell myID = e.Item.Cells[1];

int id = int.Parse(myID. Text);

if(((Button)e.C ommandSource).C ommandName == "SelectRow" )
{
DataRow dr = // fetch the record from the database using the id
}
}

---
Steven Wood

Nov 15 '05 #5

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