I'm using P/Invoke to call SendInput (using code culled
from these newsgroups!) to send mouse events to a window.
But I'm unsure how to send double-clicks. A VB6 article I
saw on SendInput suggested simply queueing two click
events, but this is not working for me, regardless of the
delay I put between clicks. So give this as a click
(where INPUT is an appropriate structure for sending the
SendInput data):
public static void Click()
{
INPUT aInput = new INPUT();
aInput.type = INPUT_MOUSE;
aInput.mi.dwFla gs = MOUSEEVENTF_LEF TDOWN;
aInput.mi.dwExt raInfo = 0;
aInput.mi.mouse Data = 0;
aInput.mi.time = 0;
int aResult = SendInput(1, ref aInput, 28 );
INPUT bInput = new INPUT();
bInput.type = INPUT_MOUSE;
bInput.mi.dwFla gs = MOUSEEVENTF_LEF TUP;
bInput.mi.dwExt raInfo = 0;
bInput.mi.mouse Data = 0;
bInput.mi.time = 0;
int bResult = SendInput(1, ref bInput, 28 );
}
The call:
Click();
Thread.Sleep(50 );
Click();
Does not work no double-click is produced no matter if the
delay is 0, 50, 100 etc. How can I send a double-click?
TIA
Richard
6  15646 
Could you tell me the idea behind simulating double click
Kalpesh
"Richard A. Lowe" <ch*****@yumspa myumYahoo.com> wrote in message
news:0e******** *************** *****@phx.gbl.. . I'm using P/Invoke to call SendInput (using code culled
from these newsgroups!) to send mouse events to a window.
But I'm unsure how to send double-clicks. A VB6 article I
saw on SendInput suggested simply queueing two click
events, but this is not working for me, regardless of the
delay I put between clicks. So give this as a click
(where INPUT is an appropriate structure for sending the
SendInput data):
public static void Click()
{
INPUT aInput = new INPUT();
aInput.type = INPUT_MOUSE;
aInput.mi.dwFla gs = MOUSEEVENTF_LEF TDOWN;
aInput.mi.dwExt raInfo = 0;
aInput.mi.mouse Data = 0;
aInput.mi.time = 0;
int aResult = SendInput(1, ref aInput, 28 );
INPUT bInput = new INPUT();
bInput.type = INPUT_MOUSE;
bInput.mi.dwFla gs = MOUSEEVENTF_LEF TUP;
bInput.mi.dwExt raInfo = 0;
bInput.mi.mouse Data = 0;
bInput.mi.time = 0;
int bResult = SendInput(1, ref bInput, 28 );
}
The call:
Click();
Thread.Sleep(50 );
Click();
Does not work no double-click is produced no matter if the
delay is 0, 50, 100 etc. How can I send a double-click?
TIA
Richard
I want to control a 'legacy' GUI that you must dbl-click
on in certain forms. This GUI will run on an undisturbed
server and has tolerance for failure. But it needs the
double-click event at certain points.
Richard -----Original Message-----
Could you tell me the idea behind simulating double click
Kalpesh
"Richard A. Lowe" <ch*****@yumspa myumYahoo.com> wrote in
messagenews:0e******* *************** ******@phx.gbl. .. I'm using P/Invoke to call SendInput (using code culled
from these newsgroups!) to send mouse events to a
window. But I'm unsure how to send double-clicks. A VB6
article I saw on SendInput suggested simply queueing two click
events, but this is not working for me, regardless of
the delay I put between clicks. So give this as a click
(where INPUT is an appropriate structure for sending the
SendInput data):
public static void Click()
{
INPUT aInput = new INPUT();
aInput.type = INPUT_MOUSE;
aInput.mi.dwFla gs = MOUSEEVENTF_LEF TDOWN;
aInput.mi.dwExt raInfo = 0;
aInput.mi.mouse Data = 0;
aInput.mi.time = 0;
int aResult = SendInput(1, ref aInput, 28 );
INPUT bInput = new INPUT();
bInput.type = INPUT_MOUSE;
bInput.mi.dwFla gs = MOUSEEVENTF_LEF TUP;
bInput.mi.dwExt raInfo = 0;
bInput.mi.mouse Data = 0;
bInput.mi.time = 0;
int bResult = SendInput(1, ref bInput, 28 );
}
The call:
Click();
Thread.Sleep(50 );
Click();
Does not work no double-click is produced no matter if
the delay is 0, 50, 100 etc. How can I send a double-
click?
TIA
Richard
.
Are you sure the structure is right? Can you post a copy of your
definition of the structure?
Jonathan Schafer
On Tue, 8 Jul 2003 05:36:59 -0700, "Richard A. Lowe"
<ch*****@yumspa myumYahoo.com> wrote: I'm using P/Invoke to call SendInput (using code culled
from these newsgroups!) to send mouse events to a window.
But I'm unsure how to send double-clicks. A VB6 article I
saw on SendInput suggested simply queueing two click
events, but this is not working for me, regardless of the
delay I put between clicks. So give this as a click
(where INPUT is an appropriate structure for sending the
SendInput data):
public static void Click()
{
INPUT aInput = new INPUT();
aInput.type = INPUT_MOUSE;
aInput.mi.dwFla gs = MOUSEEVENTF_LEF TDOWN;
aInput.mi.dwExt raInfo = 0;
aInput.mi.mouse Data = 0;
aInput.mi.time = 0;
int aResult = SendInput(1, ref aInput, 28 );
INPUT bInput = new INPUT();
bInput.type = INPUT_MOUSE;
bInput.mi.dwFla gs = MOUSEEVENTF_LEF TUP;
bInput.mi.dwExt raInfo = 0;
bInput.mi.mouse Data = 0;
bInput.mi.time = 0;
int bResult = SendInput(1, ref bInput, 28 );
}
The call:
Click();
Thread.Sleep(5 0);
Click();
Does not work no double-click is produced no matter if the
delay is 0, 50, 100 etc. How can I send a double-click?
TIA
Richard
Thanks Jonathan, I've pasted it below, however keep in
mind that other SendInput calls work as expected, both
single clicks AND mouse movements. My original assumption
was that double-clicks were a different type of input, but
then I saw the example where a double-click is created via
sending two clicks in rapid succession.
[StructLayout(La youtKind.Explic it)]
public struct MOUSEINPUT
{
[FieldOffset(0)] public int dx; //
4
[FieldOffset(4)] public int dy; //
4
[FieldOffset(8)] public int mouseData; // 4
[FieldOffset(12)] public int dwFlags; //
4
[FieldOffset(16)] public int time; //
4
[FieldOffset(20)] public int dwExtraInfo; //
4
}; -----Original Message-----
Are you sure the structure is right? Can you post a copy
of yourdefinition of the structure?
Jonathan Schafer
On Tue, 8 Jul 2003 05:36:59 -0700, "Richard A. Lowe"
<ch*****@yumsp amyumYahoo.com> wrote:
I'm using P/Invoke to call SendInput (using code culled
from these newsgroups!) to send mouse events to a
window.But I'm unsure how to send double-clicks. A VB6 article
Isaw on SendInput suggested simply queueing two click
events, but this is not working for me, regardless of
thedelay I put between clicks. So give this as a click
(where INPUT is an appropriate structure for sending the
SendInput data):
public static void Click()
{
INPUT aInput = new INPUT();
aInput.type = INPUT_MOUSE;
aInput.mi.dwFla gs = MOUSEEVENTF_LEF TDOWN;
aInput.mi.dwExt raInfo = 0;
aInput.mi.mouse Data = 0;
aInput.mi.time = 0;
int aResult = SendInput(1, ref aInput, 28 );
INPUT bInput = new INPUT();
bInput.type = INPUT_MOUSE;
bInput.mi.dwFla gs = MOUSEEVENTF_LEF TUP;
bInput.mi.dwExt raInfo = 0;
bInput.mi.mouse Data = 0;
bInput.mi.time = 0;
int bResult = SendInput(1, ref bInput, 28 );
}
The call:
Click();
Thread.Sleep( 50);
Click();
Does not work no double-click is produced no matter if
thedelay is 0, 50, 100 etc. How can I send a double-click?
TIA
Richard
.
Actually, it's started working... funny, nothing changed :( -----Original Message-----
Are you sure the structure is right? Can you post a copy
of yourdefinition of the structure?
Jonathan Schafer
On Tue, 8 Jul 2003 05:36:59 -0700, "Richard A. Lowe"
<ch*****@yumsp amyumYahoo.com> wrote:
I'm using P/Invoke to call SendInput (using code culled
from these newsgroups!) to send mouse events to a
window.But I'm unsure how to send double-clicks. A VB6 article
Isaw on SendInput suggested simply queueing two click
events, but this is not working for me, regardless of
thedelay I put between clicks. So give this as a click
(where INPUT is an appropriate structure for sending the
SendInput data):
public static void Click()
{
INPUT aInput = new INPUT();
aInput.type = INPUT_MOUSE;
aInput.mi.dwFla gs = MOUSEEVENTF_LEF TDOWN;
aInput.mi.dwExt raInfo = 0;
aInput.mi.mouse Data = 0;
aInput.mi.time = 0;
int aResult = SendInput(1, ref aInput, 28 );
INPUT bInput = new INPUT();
bInput.type = INPUT_MOUSE;
bInput.mi.dwFla gs = MOUSEEVENTF_LEF TUP;
bInput.mi.dwExt raInfo = 0;
bInput.mi.mouse Data = 0;
bInput.mi.time = 0;
int bResult = SendInput(1, ref bInput, 28 );
}
The call:
Click();
Thread.Sleep( 50);
Click();
Does not work no double-click is produced no matter if
thedelay is 0, 50, 100 etc. How can I send a double-click?
TIA
Richard
.
I searched through Google regarding SendInput and double-click. Every
post mentioned doing it the same way you were. I read in a couple of
posts that timing was an issue. This may be what you are
experiencing.
Jonathan Schafer
On Tue, 8 Jul 2003 14:38:49 -0700, "Richard A. Lowe"
<ch*****@yumspa myumYahoo.com> wrote: Actually, it's started working... funny, nothing changed :(
-----Original Message-----
Are you sure the structure is right? Can you post a copy
of yourdefinition of the structure?
Jonathan Schafer
On Tue, 8 Jul 2003 05:36:59 -0700, "Richard A. Lowe"
<ch*****@yums pamyumYahoo.com > wrote:
I'm using P/Invoke to call SendInput (using code culled
from these newsgroups!) to send mouse events to awindow.But I'm unsure how to send double-clicks. A VB6 articleIsaw on SendInput suggested simply queueing two click
events, but this is not working for me, regardless ofthedelay I put between clicks. So give this as a click
(where INPUT is an appropriate structure for sending the
SendInput data):
public static void Click()
{
INPUT aInput = new INPUT();
aInput.type = INPUT_MOUSE;
aInput.mi.dwFla gs = MOUSEEVENTF_LEF TDOWN;
aInput.mi.dwExt raInfo = 0;
aInput.mi.mouse Data = 0;
aInput.mi.time = 0;
int aResult = SendInput(1, ref aInput, 28 );
INPUT bInput = new INPUT();
bInput.type = INPUT_MOUSE;
bInput.mi.dwFla gs = MOUSEEVENTF_LEF TUP;
bInput.mi.dwExt raInfo = 0;
bInput.mi.mouse Data = 0;
bInput.mi.time = 0;
int bResult = SendInput(1, ref bInput, 28 );
}
The call:
Click();
Thread.Sleep (50);
Click();
Does not work no double-click is produced no matter ifthedelay is 0, 50, 100 etc. How can I send a double-click?
TIA
Richard
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