Specified cast is not valid.

[Arjen]

Hello,

Description: An unhandled exception occurred during the execution of the
current web request. Please review the stack trace for more information
about the error and where it originated in the code.

Exception Details: System.InvalidC astException: Specified cast is not valid.
Line 176.

Source Error:
Line 174:
Line 175:
Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;
Line 177:
Line 178: System.Web.UI.W ebControls.Imag e thumb =
(System.Web.UI. WebControls.Ima ge) e.Item.FindCont rol("thumbnail" );
Can somebody help me?

Thanks!

[Frank Drebin]

You're casting a "DataItem" as a "DataRowVie w" - that's an invalid cast!!
hehehe - I know I sound like your error, but it's true. You can't pretend a
DataItem is a DataRowView..

"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

Hello,

Description: An unhandled exception occurred during the execution of the
current web request. Please review the stack trace for more information
about the error and where it originated in the code.

Exception Details: System.InvalidC astException: Specified cast is not valid. Line 176.

Source Error:
Line 174:
Line 175:
Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;
Line 177:
Line 178: System.Web.UI.W ebControls.Imag e thumb =
(System.Web.UI. WebControls.Ima ge) e.Item.FindCont rol("thumbnail" );
Can somebody help me?

Thanks!

[Arjen]

And now?

"Frank Drebin" <no*****@imsick ofspam.com> schreef in bericht
news:eU******** **************@ newssvr28.news. prodigy.com...

You're casting a "DataItem" as a "DataRowVie w" - that's an invalid cast!!
hehehe - I know I sound like your error, but it's true. You can't pretend a DataItem is a DataRowView..

"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

Hello,

Description: An unhandled exception occurred during the execution of the
current web request. Please review the stack trace for more information
about the error and where it originated in the code.

Exception Details: System.InvalidC astException: Specified cast is not

valid.

Line 176.

Source Error:
Line 174:
Line 175:
Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;
Line 177:
Line 178: System.Web.UI.W ebControls.Imag e thumb =
(System.Web.UI. WebControls.Ima ge) e.Item.FindCont rol("thumbnail" );
Can somebody help me?

Thanks!

[Frank Drebin]

And now, you still can't. You can only coerce a variable to pretend it's a
different type - when they are close enough..

In the same way you couldn't do this:

TreeView objMyTree = (TreeView)strSo meString;

You can't cast things that are vastly different. There is no way to coerce a
string into representing a TreeView.

"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

And now?

"Frank Drebin" <no*****@imsick ofspam.com> schreef in bericht
news:eU******** **************@ newssvr28.news. prodigy.com...

You're casting a "DataItem" as a "DataRowVie w" - that's an invalid cast!! hehehe - I know I sound like your error, but it's true. You can't

pretend a

DataItem is a DataRowView..

"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

Hello,

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.InvalidC astException: Specified cast is not

valid.

Line 176.

Source Error:
Line 174:
Line 175:
Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;
Line 177:
Line 178: System.Web.UI.W ebControls.Imag e thumb =
(System.Web.UI. WebControls.Ima ge) e.Item.FindCont rol("thumbnail" );
Can somebody help me?

Thanks!

[MS News \(MS ILM\)]

Put a breaking point at DataRowView drv = (DataRowView) e.Item.DataItem ;
Then Do a Quick Watch on e.item.DataItem or find the type of e.item.DataItem
and see what type it is
Then cast to that type
"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

And now?

"Frank Drebin" <no*****@imsick ofspam.com> schreef in bericht
news:eU******** **************@ newssvr28.news. prodigy.com...

You're casting a "DataItem" as a "DataRowVie w" - that's an invalid cast!! hehehe - I know I sound like your error, but it's true. You can't

pretend a

DataItem is a DataRowView..

"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

Hello,

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.InvalidC astException: Specified cast is not

valid.

Line 176.

Source Error:
Line 174:
Line 175:
Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;
Line 177:
Line 178: System.Web.UI.W ebControls.Imag e thumb =
(System.Web.UI. WebControls.Ima ge) e.Item.FindCont rol("thumbnail" );
Can somebody help me?

Thanks!

[Arjen]

Here is the complete function:
private void myDataGrid_Item DataBound(objec t sender,
System.Web.UI.W ebControls.Data GridItemEventAr gs e) {

if (e.Item.ItemTyp e == ListItemType.It em || e.Item.ItemType ==
ListItemType.Al ternatingItem) {

DataRowView drv = (DataRowView) e.Item.DataItem ;

System.Web.UI.W ebControls.Imag e thumb = (System.Web.UI. WebControls.Ima ge)
e.Item.FindCont rol("thumbnail" );
thumb.Attribute s.Add("OnClick" , "SelectImag e('" + drv["itemId"].ToString()
+ "')");

}
}

May be this helps.





"MS News (MS ILM)" <sq**********@h otmail.com> schreef in bericht
news:up******** ******@TK2MSFTN GP09.phx.gbl...

Put a breaking point at DataRowView drv = (DataRowView) e.Item.DataItem ; Then Do a Quick Watch on e.item.DataItem or find the type of e.item.DataItem and see what type it is
Then cast to that type
"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

And now?

"Frank Drebin" <no*****@imsick ofspam.com> schreef in bericht
news:eU******** **************@ newssvr28.news. prodigy.com...

You're casting a "DataItem" as a "DataRowVie w" - that's an invalid cast!! hehehe - I know I sound like your error, but it's true. You can't pretend

a

DataItem is a DataRowView..

"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...
> Hello,
>
> Description: An unhandled exception occurred during the execution of

the > current web request. Please review the stack trace for more information > about the error and where it originated in the code.
>
> Exception Details: System.InvalidC astException: Specified cast is not valid.
> Line 176.
>
> Source Error:
>
>
> Line 174:
> Line 175:
> Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;
> Line 177:
> Line 178: System.Web.UI.W ebControls.Imag e thumb =
> (System.Web.UI. WebControls.Ima ge) e.Item.FindCont rol("thumbnail" );
>
>
> Can somebody help me?
>
> Thanks!
>
>

[Frank Drebin]

I *think* in that scenario - that e is actually your DataRowView..

Set a breakpoint and add a watch to 'e' and see what it is, if it is a
DataRowView then you can just reference things as:

e["itemId"].ToString()

hth

"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

Here is the complete function:
private void myDataGrid_Item DataBound(objec t sender,
System.Web.UI.W ebControls.Data GridItemEventAr gs e) {

if (e.Item.ItemTyp e == ListItemType.It em || e.Item.ItemType ==
ListItemType.Al ternatingItem) {

DataRowView drv = (DataRowView) e.Item.DataItem ;

System.Web.UI.W ebControls.Imag e thumb = (System.Web.UI. WebControls.Ima ge) e.Item.FindCont rol("thumbnail" );
thumb.Attribute s.Add("OnClick" , "SelectImag e('" + drv["itemId"].ToString() + "')");

}
}

May be this helps.





"MS News (MS ILM)" <sq**********@h otmail.com> schreef in bericht
news:up******** ******@TK2MSFTN GP09.phx.gbl...

Put a breaking point at DataRowView drv = (DataRowView)

e.Item.DataItem ;

Then Do a Quick Watch on e.item.DataItem or find the type of

e.item.DataItem

and see what type it is
Then cast to that type
"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

And now?

"Frank Drebin" <no*****@imsick ofspam.com> schreef in bericht
news:eU******** **************@ newssvr28.news. prodigy.com...
> You're casting a "DataItem" as a "DataRowVie w" - that's an invalid

cast!!

> hehehe - I know I sound like your error, but it's true. You can't

pretend

a
> DataItem is a DataRowView..
>
> "Arjen" <bo*****@hotmai l.com> wrote in message
> news:bh******** **@news1.tilbu1 .nb.home.nl...
> > Hello,
> >
> > Description: An unhandled exception occurred during the execution

of

the

> > current web request. Please review the stack trace for more

information

> > about the error and where it originated in the code.
> >
> > Exception Details: System.InvalidC astException: Specified cast is

not > valid.
> > Line 176.
> >
> > Source Error:
> >
> >
> > Line 174:
> > Line 175:
> > Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;
> > Line 177:
> > Line 178: System.Web.UI.W ebControls.Imag e thumb =
> > (System.Web.UI. WebControls.Ima ge) e.Item.FindCont rol("thumbnail" );
> >
> >
> > Can somebody help me?
> >
> > Thanks!
> >
> >
>
>

[MS News \(MS ILM\)]

string thetype = e.Item.DataItem .GetType();

What do you get
"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

When I change it to e["itemId"].ToString().
VS says:
Cannot apply indexing with [] to an expression of type
'System.Web.UI. WebControls.Dat aGridItemEventA rgs'

The debug says:
object DataGridItem.Da teItem
Gets or sets the data item represented by the
System.Web.UI.W ebControls.Data GridItem object in the
System.Web.UI.W ebControls.Data Grid

I don't know what to do now... you?
Thanks!



"Frank Drebin" <no*****@imsick ofspam.com> schreef in bericht
news:sj******** **************@ newssvr28.news. prodigy.com...

I *think* in that scenario - that e is actually your DataRowView..

Set a breakpoint and add a watch to 'e' and see what it is, if it is a
DataRowView then you can just reference things as:

e["itemId"].ToString()

hth

"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

Here is the complete function:
private void myDataGrid_Item DataBound(objec t sender,
System.Web.UI.W ebControls.Data GridItemEventAr gs e) {

if (e.Item.ItemTyp e == ListItemType.It em || e.Item.ItemType ==
ListItemType.Al ternatingItem) {

DataRowView drv = (DataRowView) e.Item.DataItem ;

System.Web.UI.W ebControls.Imag e thumb =

(System.Web.UI. WebControls.Ima ge)

e.Item.FindCont rol("thumbnail" );
thumb.Attribute s.Add("OnClick" , "SelectImag e('" +

drv["itemId"].ToString()

+ "')");

}
}

May be this helps.





"MS News (MS ILM)" <sq**********@h otmail.com> schreef in bericht
news:up******** ******@TK2MSFTN GP09.phx.gbl...
> Put a breaking point at DataRowView drv = (DataRowView)
e.Item.DataItem ;
> Then Do a Quick Watch on e.item.DataItem or find the type of
e.item.DataItem
> and see what type it is
> Then cast to that type
>
>
> "Arjen" <bo*****@hotmai l.com> wrote in message
> news:bh******** **@news1.tilbu1 .nb.home.nl...
> > And now?
> >
> >
> >
> >
> >
> > "Frank Drebin" <no*****@imsick ofspam.com> schreef in bericht
> > news:eU******** **************@ newssvr28.news. prodigy.com...
> > > You're casting a "DataItem" as a "DataRowVie w" - that's an invalid > cast!!
> > > hehehe - I know I sound like your error, but it's true. You can't > pretend
> > a
> > > DataItem is a DataRowView..
> > >
> > > "Arjen" <bo*****@hotmai l.com> wrote in message
> > > news:bh******** **@news1.tilbu1 .nb.home.nl...
> > > > Hello,
> > > >
> > > > Description: An unhandled exception occurred during the execution

of

> the
> > > > current web request. Please review the stack trace for more
> information
> > > > about the error and where it originated in the code.
> > > >
> > > > Exception Details: System.InvalidC astException: Specified cast

is not
> > > valid.
> > > > Line 176.
> > > >
> > > > Source Error:
> > > >
> > > >
> > > > Line 174:
> > > > Line 175:
> > > > Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;
> > > > Line 177:
> > > > Line 178: System.Web.UI.W ebControls.Imag e thumb =
> > > > (System.Web.UI. WebControls.Ima ge) e.Item.FindCont rol("thumbnail" ); > > > >
> > > >
> > > > Can somebody help me?
> > > >
> > > > Thanks!
> > > >
> > > >
> > >
> > >
> >
> >
>
>

[Kevin Spencer]

> I *think* in that scenario - that e is actually your DataRowView.

"e" is an instance of DataGridItemEve ntArgs. "e.Item" is the member to look
at. It can be one of several possible types, such as a heading section, a
footer section, or a data row. However, setting a breakpoint and doing a
watch should indeed revela what e.Item is.

--
HTH,

Kevin Spencer
Microsoft MVP
..Net Developer
http://www.takempis.com
Neither a follower nor a lender be.

"Frank Drebin" <no*****@imsick ofspam.com> wrote in message
news:sj******** **************@ newssvr28.news. prodigy.com...

I *think* in that scenario - that e is actually your DataRowView..

Set a breakpoint and add a watch to 'e' and see what it is, if it is a
DataRowView then you can just reference things as:

e["itemId"].ToString()

hth

"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...

Here is the complete function:
private void myDataGrid_Item DataBound(objec t sender,
System.Web.UI.W ebControls.Data GridItemEventAr gs e) {

if (e.Item.ItemTyp e == ListItemType.It em || e.Item.ItemType ==
ListItemType.Al ternatingItem) {

DataRowView drv = (DataRowView) e.Item.DataItem ;

System.Web.UI.W ebControls.Imag e thumb = (System.Web.UI. WebControls.Ima ge)

e.Item.FindCont rol("thumbnail" );
thumb.Attribute s.Add("OnClick" , "SelectImag e('" +

drv["itemId"].ToString()

+ "')");

}
}

May be this helps.





"MS News (MS ILM)" <sq**********@h otmail.com> schreef in bericht
news:up******** ******@TK2MSFTN GP09.phx.gbl...

Put a breaking point at DataRowView drv = (DataRowView)

e.Item.DataItem ;

Then Do a Quick Watch on e.item.DataItem or find the type of

e.item.DataItem

and see what type it is
Then cast to that type
"Arjen" <bo*****@hotmai l.com> wrote in message
news:bh******** **@news1.tilbu1 .nb.home.nl...
> And now?
>
>
>
>
>
> "Frank Drebin" <no*****@imsick ofspam.com> schreef in bericht
> news:eU******** **************@ newssvr28.news. prodigy.com...
> > You're casting a "DataItem" as a "DataRowVie w" - that's an invalid
cast!!
> > hehehe - I know I sound like your error, but it's true. You can't
pretend
> a
> > DataItem is a DataRowView..
> >
> > "Arjen" <bo*****@hotmai l.com> wrote in message
> > news:bh******** **@news1.tilbu1 .nb.home.nl...
> > > Hello,
> > >
> > > Description: An unhandled exception occurred during the execution of

the
> > > current web request. Please review the stack trace for more
information
> > > about the error and where it originated in the code.
> > >
> > > Exception Details: System.InvalidC astException: Specified cast

is not

> > valid.
> > > Line 176.
> > >
> > > Source Error:
> > >
> > >
> > > Line 174:
> > > Line 175:
> > > Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;
> > > Line 177:
> > > Line 178: System.Web.UI.W ebControls.Imag e thumb =
> > > (System.Web.UI. WebControls.Ima ge)

e.Item.FindCont rol("thumbnail" ); > > >
> > >
> > > Can somebody help me?
> > >
> > > Thanks!
> > >
> > >
> >
> >
>
>

[Carl Prothman [MVP]]

"Arjen" <bo*****@hotmai l.com> wrote

Line 176: DataRowView drv = (DataRowView) e.Item.DataItem ;

I use now a datagrid and the IBS a datalist.

Some body else a solution?

Arjen,
If you use a DataSet to bind the DataList, then that is the correct syntax.

However, if you use a SqlDataReader to bind, then you must cast the
DataItem to a System.Data.Com mon.DbDataRecor d.
e.g.
System.Data.Com mon.DbDataRecor d dbDataRecord =
(System.Data.Co mmon.DbDataReco rd) e.Item.DataItem ;
String s = dbDataRecord.Ge tString(0);

--

Thanks,
Carl Prothman
Microsoft ASP.NET MVP
http://www.able-consulting.com