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Control flow problem

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  1. class BreakWithLabelDemo {
  2.     public static void main(String[] args) {
  3.  
  4.         int[][] arrayOfInts = { { 32, 87, 3, 589 },
  5.                                 { 12, 1076, 2000, 8 },
  6.                                 { 622, 127, 77, 955 }
  7.                               };
  8.         int searchfor = 12;
  9.  
  10.         int i;
  11.         int j = 0;
  12.         boolean foundIt = false;
  13.  
  14.     search:
  15.         for (i = 0; i < arrayOfInts.length; i++) {
  16.             for (j = 0; j < arrayOfInts[i].length; j++) {
  17.                 if (arrayOfInts[i][j] == searchfor) {
  18.                     foundIt = true;
  19.                     break search;
  20.                 }
  21.             }
  22.         }
  23.  
  24.         if (foundIt) {
  25.             System.out.println("Found " + searchfor +
  26.                                " at " + i + ", " + j);
  27.         } else {
  28.             System.out.println(searchfor
  29.                                + " not in the array");
  30.         }
  31.     }
  32. }
Found 12 at 1, 0


Q:-
how come the answer is 1, 0....i think it sld be 0, 1..because 12 is at position 01...where ' i 'stands for row and ' j ' stands for column...please explain me where am i wrong.
Sep 16 '08 #1
2 1388
JosAH
11,448 Expert 8TB
For a two dimensional matrix the first index denotes the rows and the second
one the columns in the rows, so row #0 is { 32, 87, 3, 589 } while row #1 is
{ 12, 1076, 2000, 8 } and row #2 is { 622, 127, 77, 955 }.

Number 12 occurs in row #1 and column #0

kind regards,

Jos
Sep 16 '08 #2
Vneha
10
Thanks,

I got it now.

regards,

Neha
Sep 16 '08 #3

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