Control flow problem

[Vneha]

class BreakWithLabelDemo {
    public static void main(String[] args) {
 
        int[][] arrayOfInts = { { 32, 87, 3, 589 },
                                { 12, 1076, 2000, 8 },
                                { 622, 127, 77, 955 }
                              };
        int searchfor = 12;
 
        int i;
        int j = 0;
        boolean foundIt = false;
 
    search:
        for (i = 0; i < arrayOfInts.length; i++) {
            for (j = 0; j < arrayOfInts[i].length; j++) {
                if (arrayOfInts[i][j] == searchfor) {
                    foundIt = true;
                    break search;
                }
            }
        }
 
        if (foundIt) {
            System.out.println("Found " + searchfor +
                               " at " + i + ", " + j);
        } else {
            System.out.println(searchfor
                               + " not in the array");
        }
    }
}

Found 12 at 1, 0


Q:-
how come the answer is 1, 0....i think it sld be 0, 1..because 12 is at position 01...where ' i 'stands for row and ' j ' stands for column...please explain me where am i wrong.

[JosAH]

For a two dimensional matrix the first index denotes the rows and the second
one the columns in the rows, so row #0 is { 32, 87, 3, 589 } while row #1 is
{ 12, 1076, 2000, 8 } and row #2 is { 622, 127, 77, 955 }.

Number 12 occurs in row #1 and column #0

kind regards,

Jos

[Vneha]

Thanks,

I got it now.

regards,

Neha