Using XSL to reformat XML by removing nested DIV elements but retaining text

[xscape]

Hi all,

I have an XML file which contains a load of nested divs. I'm trying to write some XSL to create a new XML file with all the excess divs removed, but I want to retain the content and place this in paragraph tags.

Here is a snippet of the code:

<?xml version="1.0" encoding="UTF-8"?>
<Content>
    <div>
        <div>this is some content</div>
        <div>
            <div>
                <div>this is some more content</div>
                <div>
                    <div>
                        <div>and some more and more and more</div>
                        <div>
                            <div>
                                <div>more more more more</div>
                            </div>
                        </div>
                    </div>
                </div>
            </div>
        </div>
    </div>
</Content>

The desired output is:

<?xml version="1.0" encoding="UTF-8"?>
<Content>
    <p>this is some content</p>
    <p>this is some more content</p>
    <p>and some more and more and more</p>
    <p>more more more more</p>
</Content>

Sounds easy, but I don't what is the best way to handle this, could I use a for-each to iterate through the elements, or write a recursive template to handle the divs?

Any help much appreciated.

[dorinbogdan]

Welcome to TheScripts TSDN...

Good question, I would try for-each loop, which is easier to handle for me.
(I never used recursive templates, but it may work).
If need more help please post some XSL code to test on.
We don't provide full source code (it's against site rules), just suggestions and code snippets.

[xscape]

Hi dorinbogdan,

Thank you for the warm welcome!
I think I have solved the problem - as you so rightly suggested, I used a for-each loop:

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:output method="xml" indent="yes"/>
 
 
    <xsl:template match="/">
        <xsl:element name="Content">
            <xsl:for-each select=".//div">
                <xsl:if test="count(child::div) = 0">
                    <xsl:call-template name="handle_div">
                        <xsl:with-param name="div_content" select="."/>
                    </xsl:call-template>
                </xsl:if>
            </xsl:for-each>
        </xsl:element>
    </xsl:template>
 
    <xsl:template name="handle_div">
        <xsl:param name="div_content" />
            <xsl:element name="p">
                <xsl:value-of select="$div_content"/>
            </xsl:element>
    </xsl:template>
 
</xsl:stylesheet>

The above XSL seems to work, though can you see any problems with this code?

Many thanks.

[dorinbogdan]

Nice code.
If it meets the requirements I have nothing to say, it look compact and well-formed.

God bless you,
Dorin.