XSL doubt!

[jai80]

Hi Frenz,

am working with xsl, and with a specific criteria, am trying to change the font color of the date value, as it can be seen from the code.
Its a table with many rows. Instead of changing the color of the date value in that particular td of the table, i want to change the background color of tht td for tht date. please help me how to modify my code. its urgent.

[html]<xsl:template match="//row" >
<xsl:variable name='JoinCntFlag' select="//row[@Element='CountFlag' and @Date=$TDate]/@Cnt"/>
<tr>
<td class="text1" align="left" style="background-color: gainsbro">
<a class="link1">
<xsl:attribute name="href" >javascript:OpenVisitType('<xsl:value-of select="@Date" />')
</xsl:attribute>
<xsl:choose>
<xsl:when test ="$JoinCntFlag = 1" >
<font color="brown"><xsl:value-of select="@Date"/> </font>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="@Date"/>
</xsl:otherwise>
</xsl:choose>
</a>
</td>
<td>.........</td>
</tr>
....
</xsl:template>[/html]

Thanks,
jai

[dorinbogdan]

Try something like this:
[html]....
<td class="text1" align="left">
<xsl:attribute name="style">
<xsl:choose>
<xsl:when test ="$JoinCntFlag = 1" >
'background-color:red'
</xsl:when>
<xsl:otherwise>
'background-color:blue'
</xsl:otherwise>
</xsl:choose>
</xsl:attribute>
<a class="link1">
<xsl:attribute name="href">javascript:OpenVisitType('<xsl:value-of select="@Date" />')
</xsl:attribute>
<xsl:value-of select="@Date"/>
</a>
</td>
....[/html]