How to find Me in a library procedure

[Academia]

I have a procedure and in the procedure I use "Me"
Since I have multiple copies of this procedure in various places I place it
into a library as a Shared Sub.

The problem is in the library I can't use Me so I add an argument like:
( ByVal c as Control, ...)

and call it with Me as the parameter:
Library.DoSub(Me, ...)

Is there a another way?

Can't the procedure figure out who c is from the stack some how?

I've been looking at StackTrace but can't see the solution there.

Can you suggest how this can be done?

Thanks in advance

[Cor Ligthert [MVP]]

Hi Bill,

Armin is one of the longest and most respected community members of the
International and German VB for Net newsgroups and at least I want to keep
it like that.

He has no problems with any discussion, however in my idea is he not waiting
on a learning tone from a MVP.

Be aware however that in answering questions, we don't always want to be
exactly correct.
That an OP understand it and helped with that is more important than any
theoretical explanation.

I know that Armin knows more from VB (including VB6) than a lot of MVP's

If you want any deeper information about that, then mail Jay, Herfried or
me.

Sorry Armin, I could not resist.

Cor

[Armin Zingler]

"Cor Ligthert [MVP]" <no************@planet.nlschrieb

Sorry Armin, I could not resist.

Thanks for the kind words, Cor! I really appreciate all your
contributions, too. However, please no personality discussion. I don't
feel that Bill was disrespectful. I only think it was a kind of
misunderstanding each other.
Armin