Unlocking file when assigned to PictureBox

[Mark]

Hello,

Say I write a picture file to: 'c:\test.jpg'

Then I assign this picture to a picturebox
PbFoto.Image = Image.Fromfile("c:\test.jpg")

Next I want the overrwrite the file test.jpg with another picture.

When running, he says the file is in use when I want to overwrite it.
(if not assignd to the picture box, I can overwritte as many as I want)

I've tried 'PbFoto.Image = Nothing', but that didn't help also.

Anyone an idea how to free the file?

[Chris Dunaway]

On Wed, 22 Sep 2004 13:25:03 +0200, Mark wrote:

Hello,

Say I write a picture file to: 'c:\test.jpg'

Then I assign this picture to a picturebox
PbFoto.Image = Image.Fromfile("c:\test.jpg")

Next I want the overrwrite the file test.jpg with another picture.

When running, he says the file is in use when I want to overwrite it.
(if not assignd to the picture box, I can overwritte as many as I want)

I've tried 'PbFoto.Image = Nothing', but that didn't help also.

Anyone an idea how to free the file?

Look elsewhere in these groups for more information, but I believe the
solution offered is to use the FromStream method instead of using the
Image.FromFile method. When using FromStream, the file is not locked.

Perhaps this code can help:

Imports System.IO
Imports System.Drawing

Dim fs As System.IO.FileStream
fs = New FileStream("C:\test.jpg", FileMode.Open, FileAccess.Read)
PictureBox1.Image = Image.FromStream(fs)
fs.Close()
--
Chris

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[Atara]

for memory optimization reasons GDI+ locks the file.

' --------------------------------------
' 1. Final Version:
'! myP.Image = Image.FromFile(src)
' --------------------------------------
' 2. Edit Version:
' based on MSDN:
' Image File Is Locked When You Set the PictureBox Image
' Property to a File
' http://support.microsoft.com/default...id=kb;;Q309482
Dim fs As System.IO.FileStream
fs = New System.IO.FileStream(src, IO.FileMode.Open, IO.FileAccess.Read)
'TODO: Add exeption: 'Directory not found'
'TODO: Add exeption: 'System.IO.FileNotFoundException'
myP.Image = System.Drawing.Image.FromStream(fs)
fs.Close()
' --------------------------------------

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