Regular Expression or Code

[Matt]

I have a problem and I am looking for suggestions. Here is the situation:

I am writing a VB.NET app to convert a string into a markup language used in
a program we have at my company. The languange handles CrLf's very stragly.
It doesn't ignore them like HTML. It will read and print them when there
are two or more in a row, but it ignores a single CRLF. To do a single line
break, you need to use the command .br; however, two CRLF's register as two
line breaks. That's right. I said two. Oh, just to make things a little
more challenging, replacing every CRLF with a .br doesn't work. The app
only reads the first .br and ignores the rest..

I can't say much for the markup languange , but it is what I have to work
with. Here is what I need to do when I parse the string:

I need to replace a single CRLF with a .br.
I need to leave two or more CRLFs in a row the way they are.

I am looking for a regular expression that would accomplish this, but code
that does the same thing would work too. In other words, any suggestions
would be appreciated.

Thanks,
Matt

[Cor Ligthert]

Matt,

To make it more clear to me, you need to do something as

mytext = mytext.replace(" " & VBCRLF & " ",".br")

Cor

I have a problem and I am looking for suggestions. Here is the situation:

I am writing a VB.NET app to convert a string into a markup language used in a program we have at my company. The languange handles CrLf's very stragly. It doesn't ignore them like HTML. It will read and print them when there
are two or more in a row, but it ignores a single CRLF. To do a single line break, you need to use the command .br; however, two CRLF's register as two line breaks. That's right. I said two. Oh, just to make things a little
more challenging, replacing every CRLF with a .br doesn't work. The app
only reads the first .br and ignores the rest..

I can't say much for the markup languange , but it is what I have to work
with. Here is what I need to do when I parse the string:

I need to replace a single CRLF with a .br.
I need to leave two or more CRLFs in a row the way they are.

I am looking for a regular expression that would accomplish this, but code
that does the same thing would work too. In other words, any suggestions
would be appreciated.

Thanks,
Matt

[Cor Ligthert]

Doh, error

mytext = mytext.replace(VBCRLF & VBCRLF, "@#AnonexistingText&^")
mytext = mytext.replace(VBCRLF, ".br")
mytext = mytext.replace("@#AnonexistingText&^", VBCRLF & VBCRLF)

Keep in mind that the replace is moslty more than 100 times faster than the
regex.

I hope this helps?

Cor

[Matt]

Very, very nearly what I needed. Your approach helped me find the solution.
I only had to add one more replace to make sure the .br wasn't there AT ALL
if there was more then one vbCrLf:

mytext = mytext.replace(vbCrLf & vbCrLf, "@#AnonexistingText&^")
mytext = mytext.Replace(vbCrLf, vbCrLf & ".br" & vbCrLf)
mytext = mytext.Replace("@#AnonexistingText&^", vbCrLf & vbCrLf)
mytext = mytext.Replace(vbCrLf & vbCrLf & ".br", vbCrLf)

"Cor Ligthert" <no**********@planet.nl> wrote in message
news:eV**************@TK2MSFTNGP09.phx.gbl...

Doh, error

mytext = mytext.replace(VBCRLF & VBCRLF, "@#AnonexistingText&^")
mytext = mytext.replace(VBCRLF, ".br")
mytext = mytext.replace("@#AnonexistingText&^", VBCRLF & VBCRLF)

Keep in mind that the replace is moslty more than 100 times faster than the regex.

I hope this helps?

Cor

[Matt]

Oh, and by the way, thanks! =)

"Cor Ligthert" <no**********@planet.nl> wrote in message
news:eV**************@TK2MSFTNGP09.phx.gbl...

Doh, error

mytext = mytext.replace(VBCRLF & VBCRLF, "@#AnonexistingText&^")
mytext = mytext.replace(VBCRLF, ".br")
mytext = mytext.replace("@#AnonexistingText&^", VBCRLF & VBCRLF)

Keep in mind that the replace is moslty more than 100 times faster than the regex.

I hope this helps?

Cor

[Jay B. Harlow [MVP - Outlook]]

Matt,
With 4 or more replaces in a row like that I would consider using a
StringBuilder instead of re-creating the string each time.

Something like:

Dim sb As New System.Text.StringBuilder(mytext, mytext.Length * 2)

sb.Replace(vbCrLf & vbCrLf, "@#AnonexistingText&^")
sb.Replace(vbCrLf, vbCrLf & ".br" & vbCrLf)
sb.Replace("@#AnonexistingText&^", vbCrLf & vbCrLf)
sb.Replace(vbCrLf & vbCrLf & ".br", vbCrLf)

mytext = sb.ToString()

The "mytext.Length * 2" is how big a buffer the StringBuilder is going to
work with, I would attempt to calculate the largest result string
(intermediate also) that would occur from the Replacements...

With 3 or 4 replacements I would probably go with your code as is, unless
there was a performance problem, then I would try the StringBuilder to see
if that helped or hurt.

Hope this helps
Jay

"Matt" <ki*******@hotmail.com> wrote in message
news:d52Uc.29867$Jo1.16794@lakeread01...

Very, very nearly what I needed. Your approach helped me find the solution. I only had to add one more replace to make sure the .br wasn't there AT ALL if there was more then one vbCrLf:

mytext = mytext.replace(vbCrLf & vbCrLf, "@#AnonexistingText&^")
mytext = mytext.Replace(vbCrLf, vbCrLf & ".br" & vbCrLf)
mytext = mytext.Replace("@#AnonexistingText&^", vbCrLf & vbCrLf)
mytext = mytext.Replace(vbCrLf & vbCrLf & ".br", vbCrLf)

"Cor Ligthert" <no**********@planet.nl> wrote in message
news:eV**************@TK2MSFTNGP09.phx.gbl...

Doh, error

mytext = mytext.replace(VBCRLF & VBCRLF, "@#AnonexistingText&^")
mytext = mytext.replace(VBCRLF, ".br")
mytext = mytext.replace("@#AnonexistingText&^", VBCRLF & VBCRLF)

Keep in mind that the replace is moslty more than 100 times faster than

the

regex.

I hope this helps?

Cor