473,231 Members | 1,821 Online
Bytes | Software Development & Data Engineering Community
Post Job

Home Posts Topics Members FAQ

Join Bytes to post your question to a community of 473,231 software developers and data experts.

Regular Expression Help!

Not having used regular expressions much, I need some help.

Given a string... "This\0Guy\0Needs\0Some\0Help\0\0\0\0\0"
Need result as array of strings... "This","Guy", "Needs", "Some",
"Help"

Where '\0' is a literal zero-byte.

I think I need two regular expressions? One to strip the multiple
instances of '\0' bytes, and another to split the string.

Regex.Split works fine for the split, but I am having trouble getting
a regular expression to find the multiple '\0' instances, but leave
the single '\0' references alone.

Thanks!
Nov 21 '05 #1
9 1741
use the vb.net function split, not regex
Frank
"Schorschi" <Sc*******@DSLExtreme.COM> wrote in message
news:21**************************@posting.google.c om...
Not having used regular expressions much, I need some help.

Given a string... "This\0Guy\0Needs\0Some\0Help\0\0\0\0\0"
Need result as array of strings... "This","Guy", "Needs", "Some",
"Help"

Where '\0' is a literal zero-byte.

I think I need two regular expressions? One to strip the multiple
instances of '\0' bytes, and another to split the string.

Regex.Split works fine for the split, but I am having trouble getting
a regular expression to find the multiple '\0' instances, but leave
the single '\0' references alone.

Thanks!

Nov 21 '05 #2
bad advice.

"Frank" <fr***@frank.com> wrote in message
news:cf**********@news2.tilbu1.nb.home.nl...
| use the vb.net function split, not regex
| Frank
| "Schorschi" <Sc*******@DSLExtreme.COM> wrote in message
| news:21**************************@posting.google.c om...
| > Not having used regular expressions much, I need some help.
| >
| > Given a string... "This\0Guy\0Needs\0Some\0Help\0\0\0\0\0"
| > Need result as array of strings... "This","Guy", "Needs", "Some",
| > "Help"
| >
| > Where '\0' is a literal zero-byte.
| >
| > I think I need two regular expressions? One to strip the multiple
| > instances of '\0' bytes, and another to split the string.
| >
| > Regex.Split works fine for the split, but I am having trouble getting
| > a regular expression to find the multiple '\0' instances, but leave
| > the single '\0' references alone.
| >
| > Thanks!
|
|
Nov 21 '05 #3
this is a classic!

"((.)\1*)" ' any single character followed by same character 0 or more
times.

that's a very general approach...but just for your \0...

"((\0)\1*)" ' any \0 followed by 0 or more occurances of \0

hth,

steve

btw, tons of regex tools out there for .net...google for ".net regex gui". i
use "the regulator" and "regex coach" quite a bit when testing regex
patterns.
"Schorschi" <Sc*******@DSLExtreme.COM> wrote in message
news:21**************************@posting.google.c om...
| Not having used regular expressions much, I need some help.
|
| Given a string... "This\0Guy\0Needs\0Some\0Help\0\0\0\0\0"
| Need result as array of strings... "This","Guy", "Needs", "Some",
| "Help"
|
| Where '\0' is a literal zero-byte.
|
| I think I need two regular expressions? One to strip the multiple
| instances of '\0' bytes, and another to split the string.
|
| Regex.Split works fine for the split, but I am having trouble getting
| a regular expression to find the multiple '\0' instances, but leave
| the single '\0' references alone.
|
| Thanks!
Nov 21 '05 #4
"Schorschi" <Sc*******@DSLExtreme.COM> skrev i en meddelelse
news:21**************************@posting.google.c om...
Given a string... "This\0Guy\0Needs\0Some\0Help\0\0\0\0\0"
Need result as array of strings... "This","Guy", "Needs", "Some",
"Help"


This single regular expression + code will do the job:

Dim oRegex As Regex
Dim sInput As String
Dim oCaptures As CaptureCollection
Dim asResult As String()

sInput = "This" & Chr(0) & "Guy" & Chr(0) & "Needs" & Chr(0) & _
"Some" & Chr(0) & "Help" & Chr(0) & Chr(0) & Chr(0) & Chr(0) & Chr(0)

oRegex = New Regex("^\0*((?<substring>[^\0]+)\0*)*$")
oCaptures = oRegex.Match(sInput).Groups("substring").Captures
ReDim asResult(oCaptures.Count - 1)
For i As Integer = 0 To oCaptures.Count - 1
asResult(i) = oCaptures(i).ToString
Next
/Jens
--
Jens Christian Mikkelsen
http://www.jcmikkelsen.dk
Nov 21 '05 #5
Why Steve? Isn't it precisely what Schorschi wants?
Regards
Frank
"steve" <a@b.com> wrote in message
news:10*************@corp.supernews.com...
bad advice.

"Frank" <fr***@frank.com> wrote in message
news:cf**********@news2.tilbu1.nb.home.nl...
| use the vb.net function split, not regex
| Frank
| "Schorschi" <Sc*******@DSLExtreme.COM> wrote in message
| news:21**************************@posting.google.c om...
| > Not having used regular expressions much, I need some help.
| >
| > Given a string... "This\0Guy\0Needs\0Some\0Help\0\0\0\0\0"
| > Need result as array of strings... "This","Guy", "Needs", "Some",
| > "Help"
| >
| > Where '\0' is a literal zero-byte.
| >
| > I think I need two regular expressions? One to strip the multiple
| > instances of '\0' bytes, and another to split the string.
| >
| > Regex.Split works fine for the split, but I am having trouble getting
| > a regular expression to find the multiple '\0' instances, but leave
| > the single '\0' references alone.
| >
| > Thanks!
|
|

Nov 21 '05 #6
| Isn't it precisely what Schorschi wants?

no, it's not precisely what he wants...this is:

| > | > Regex.Split works fine for the split, but I am having trouble
getting
| > | > a regular expression to find the multiple '\0' instances, but leave
| > | > the single '\0' references alone.

you're making assumptions about the string he's processing. albeit, your
assumption is probably fairly accurate. however, not enough info is provided
in order to make a logically correct "leap". for instance, what if he know's
the string has exactly what should turn out to be three elements in his
final array? but, these three elements could have the repetative \0's any
number of times w/n the original string at any location in the string. were
he to just use the split method, he'd have to loop through the array to get
all the elements and see which one's had something other than "". if he can
get his final array to constant dimensions, i.e. three, then he can create
constants by which he can refer to each element of the final array...ex.,
NAME, DESCRIPTION, ID, etc. makes the code easier to follow and maintain. i
digress...as it is, you have to give him the ability to leave only one
instance of \0 where it is immediately followed by a continuous repetion of
\0...unless you want to give him something other than what he "precisely"
wants.
Nov 21 '05 #7
Schorschi,
In addition to the other comments.
Regex.Split works fine for the split, but I am having trouble getting
a regular expression to find the multiple '\0' instances, but leave
the single '\0' references alone. You can use "\0+" to match on one or more occurrences of a null char.
Remember there are three Split functions in .NET:

Use Microsoft.VisualBasic.Strings.Split if you need to split a string based
on a specific word (string). It is the Split function from VB6.

Use System.String.Split if you need to split a string based on a collection
of specific characters. Each individual character is its own delimiter.

Use System.Text.RegularExpressions.RegEx.Split to split based
on matching patterns.

In your example I would consider using RegEx.Split as it sounds like you do
not want duplicate empty elements.

Something like:

Const pattern As String = "\0+"
Dim rex As New Regex(pattern)
Dim input As String = "This\0Guy\0Needs\0Some\0Help\0\0\0\0\0"
input = input.Replace("\0", ChrW(0))

Dim words() As String = rex.Split(input)
For Each word As String In words
Debug.WriteLine(word)
Next

The one caveat is the trailing "\0" causes an empty element (which sounds
like its understandable). I would use String.Trim before the Split if this
is a problem...

Note the above works for "This\0\0\0Guy\0Needs\0\0Some\0Help\0\0\0\0\0"

Hope this helps
Jay
"Schorschi" <Sc*******@DSLExtreme.COM> wrote in message
news:21**************************@posting.google.c om... Not having used regular expressions much, I need some help.

Given a string... "This\0Guy\0Needs\0Some\0Help\0\0\0\0\0"
Need result as array of strings... "This","Guy", "Needs", "Some",
"Help"

Where '\0' is a literal zero-byte.

I think I need two regular expressions? One to strip the multiple
instances of '\0' bytes, and another to split the string.

Regex.Split works fine for the split, but I am having trouble getting
a regular expression to find the multiple '\0' instances, but leave
the single '\0' references alone.

Thanks!

Nov 21 '05 #8
Steve, you still have not told me why the vb.net split function is bad
advice. I'd like to know.
Thanks
Frank
"steve" <a@b.com> wrote in message
news:10*************@corp.supernews.com...
bad advice.

"Frank" <fr***@frank.com> wrote in message
news:cf**********@news2.tilbu1.nb.home.nl...
| use the vb.net function split, not regex
| Frank
| "Schorschi" <Sc*******@DSLExtreme.COM> wrote in message
| news:21**************************@posting.google.c om...
| > Not having used regular expressions much, I need some help.
| >
| > Given a string... "This\0Guy\0Needs\0Some\0Help\0\0\0\0\0"
| > Need result as array of strings... "This","Guy", "Needs", "Some",
| > "Help"
| >
| > Where '\0' is a literal zero-byte.
| >
| > I think I need two regular expressions? One to strip the multiple
| > instances of '\0' bytes, and another to split the string.
| >
| > Regex.Split works fine for the split, but I am having trouble getting
| > a regular expression to find the multiple '\0' instances, but leave
| > the single '\0' references alone.
| >
| > Thanks!
|
|

Nov 21 '05 #9
why not just use replace

string.replace("\0","")
then use regex or normal split?

just my 2 cents

WStorey II

"steve" wrote:
| Isn't it precisely what Schorschi wants?

no, it's not precisely what he wants...this is:

| > | > Regex.Split works fine for the split, but I am having trouble
getting
| > | > a regular expression to find the multiple '\0' instances, but leave
| > | > the single '\0' references alone.

you're making assumptions about the string he's processing. albeit, your
assumption is probably fairly accurate. however, not enough info is provided
in order to make a logically correct "leap". for instance, what if he know's
the string has exactly what should turn out to be three elements in his
final array? but, these three elements could have the repetative \0's any
number of times w/n the original string at any location in the string. were
he to just use the split method, he'd have to loop through the array to get
all the elements and see which one's had something other than "". if he can
get his final array to constant dimensions, i.e. three, then he can create
constants by which he can refer to each element of the final array...ex.,
NAME, DESCRIPTION, ID, etc. makes the code easier to follow and maintain. i
digress...as it is, you have to give him the ability to leave only one
instance of \0 where it is immediately followed by a continuous repetion of
\0...unless you want to give him something other than what he "precisely"
wants.

Nov 21 '05 #10

This thread has been closed and replies have been disabled. Please start a new discussion.

Similar topics

5
by: Bradley Plett | last post by:
I'm hopeless at regular expressions (I just don't use them often enough to gain/maintain knowledge), but I need one now and am looking for help. I need to parse through a document to find a URL,...
4
by: Neri | last post by:
Some document processing program I write has to deal with documents that have headers and footers that are unnecessary for the main processing part. Therefore, I'm using a regular expression to go...
10
by: Lee Kuhn | last post by:
I am trying the create a regular expression that will essentially match characters in the middle of a fixed-length string. The string may be any characters, but will always be the same length. In...
3
by: James D. Marshall | last post by:
The issue at hand, I believe is my comprehension of using regular expression, specially to assist in replacing the expression with other text. using regular expression (\s*) my understanding is...
7
by: Billa | last post by:
Hi, I am replaceing a big string using different regular expressions (see some example at the end of the message). The problem is whenever I apply a "replace" it makes a new copy of string and I...
9
by: Pete Davis | last post by:
I'm using regular expressions to extract some data and some links from some web pages. I download the page and then I want to get a list of certain links. For building regular expressions, I use...
3
by: Zach | last post by:
Hello, Please forgive if this is not the most appropriate newsgroup for this question. Unfortunately I didn't find a newsgroup specific to regular expressions. I have the following regular...
25
by: Mike | last post by:
I have a regular expression (^(.+)(?=\s*).*\1 ) that results in matches. I would like to get what the actual regular expression is. In other words, when I apply ^(.+)(?=\s*).*\1 to " HEART...
3
by: Mr.Steskal | last post by:
Posted: Wed Jul 11, 2007 7:01 am Post subject: Regular Expression Help -------------------------------------------------------------------------------- I need help writing a regular...
18
by: Lit | last post by:
Hi, I am looking for a Regular expression for a password for my RegExp ValidationControl Requirements are, At least 8 characters long. At least one digit At least one upper case character
3
isladogs
by: isladogs | last post by:
The next Access Europe meeting will be on Wednesday 3 Jan 2024 starting at 18:00 UK time (6PM UTC) and finishing at about 19:15 (7.15PM). For other local times, please check World Time Buddy In...
0
by: jianzs | last post by:
Introduction Cloud-native applications are conventionally identified as those designed and nurtured on cloud infrastructure. Such applications, rooted in cloud technologies, skillfully benefit from...
0
by: abbasky | last post by:
### Vandf component communication method one: data sharing ​ Vandf components can achieve data exchange through data sharing, state sharing, events, and other methods. Vandf's data exchange method...
0
by: fareedcanada | last post by:
Hello I am trying to split number on their count. suppose i have 121314151617 (12cnt) then number should be split like 12,13,14,15,16,17 and if 11314151617 (11cnt) then should be split like...
0
by: stefan129 | last post by:
Hey forum members, I'm exploring options for SSL certificates for multiple domains. Has anyone had experience with multi-domain SSL certificates? Any recommendations on reliable providers or specific...
0
Git
by: egorbl4 | last post by:
Скачал я git, хотел начать настройку, а там вылезло вот это Что это? Что мне с этим делать? ...
0
by: MeoLessi9 | last post by:
I have VirtualBox installed on Windows 11 and now I would like to install Kali on a virtual machine. However, on the official website, I see two options: "Installer images" and "Virtual machines"....
0
by: DolphinDB | last post by:
The formulas of 101 quantitative trading alphas used by WorldQuant were presented in the paper 101 Formulaic Alphas. However, some formulas are complex, leading to challenges in calculation. Take...
0
by: Aftab Ahmad | last post by:
So, I have written a code for a cmd called "Send WhatsApp Message" to open and send WhatsApp messaage. The code is given below. Dim IE As Object Set IE =...

By using Bytes.com and it's services, you agree to our Privacy Policy and Terms of Use.

To disable or enable advertisements and analytics tracking please visit the manage ads & tracking page.