problem with if statement

[ZS369]

Hi! When one types a user that doesnt exist it immediately goes to the else statement instead of into the if statement and prints user doesnt exist how do i change this? This is my function:

function viewUserProperties {
echo "Which user would you like to view?"
read user

if [[ $user == 0 ]];
then
echo "User does not exist!"
else
printf "\nUser view for $user\n"
printf "\n-15s\n %-15s\n %-15s\n %-15s\n
%-15s\n%-15s\n%-15s\n", "Username" "Password" "User ID" "Group ID" "Directory" "Shell"
getent passwd $user | tr ':' '\n'

fi
}


Output now:
view for arnold

Username
Password
User ID
Group ID
Directory
Shell
arnold
x
1003
1003
/home/arnold
/bin/bash

I also wish to change the output into table format as seen below. How do i do that? Thanks in advance!

view for arnold

Username arnold
Password x
User ID 1003
Group ID 1003
Directory /home/arnold
Shell /bin/bash

[Luuk]

You are not checking if your user exists, or not!
Also if you do not enter a username, $user will be '', and $user will only be 0 if you type-in '0'.

I rewrote your code to this:

#!/bin/bash
#set -x
read user
getentUser=$(getent passwd $user)
if [[ $? != 0 ]];
then
                echo "User does not exist!"
else
                printf "\nUser view for $user\n"
 
                (
                echo "Username:Password:User ID:Group ID:Directory:Shell"
                echo "$getentUser"
                ) | gawk -F: 'NR==1{ for (i=1; i<=6; i++) { a[i]=$i }}
                NR==2{ for (i=1; i<=6; i++) { b[i]=$i }}
                END{ for (i=1; i<=6; i++){ printf "%-15s: %-15s\n", a[i], b[i]}}'
fi
 

on line#4 the existance if the user is tested
line#5 if the returnvalue of getent is not equal to 0, than $user does not exist
lines#11-#13 create the output on 2 lines, with fields separated by ':
lines#14-#16 use GAWK to display a table

if you remove the '#' in line#2, you will see every line before it gets evaluated.