How to reverse a list for the purpose of finding the previous item with a condition ?

[amskape]

Dear friends,
I try to find the forward and backward content of a play list . The main item is identified using <h1> tag ...
I wrote a code for forward item which works fine as below:

    if(direction == "forward"):
    counter = 0
    for i in range(self.pos_indice,len(self.indice)):
        if(self.indice[i+1].tagName == "h1"):
           break
        else:
           counter = counter+1
    return counter+1
 
 

but in reverse my code fails as shown below:

 
if(direction == "backword"):
    rev_counter = self.pos_indice
    for j in range(self.pos_indice,0,-1):
        if(self.indice[j+1].tagName == "h1"):
           break
        else:
           rev_counter = rev_counter + 1
    return rev_counter+1
 

Please advise with a solution fast

Thanks
Anes

[Luk3r]

Python has a built-in reversed() function which can be used in a For loop.

[amskape]

Dear Luk3r,
I used following code for purpose and feel works fine 90% !!

 
    if(direction == "backword"):
    rev_counter = 0
    for j in range(self.pos_indice,-1,-1):
 
        if(self.indice[j-1].tagName == "h1"):
           break
        else:
           rev_counter = rev_counter + 1
    return rev_counter+1
 

Please advise any further modifications....

Thanks
Anes