merging files, each file in a new line

[thistle]

I have this code to merge files. the files language is persian. it merges them but I want each file to be written in a new line. for example if I have 9 files, the output should be 9 lines. each line is one file. the problem is that I don't know where to put replace('\n', " ") to omit newlines of a file and where to add '\n' to go to the next file.

import os,shutil
path = 'فناوري'
f=open("wwww.txt","a", encoding = 'utf-8')
for r,d,fi in os.walk(path):
    for files in fi:
        if files.endswith(".txt"):                         
            g=open(os.path.join(r,files), encoding = 'utf-8')
            shutil.copyfileobj(g,f)
            g.close()
f.close()

[bvdet]

Given a list of filenames, create a string from the contents of each file. You can then write the string to your output file.

>>> files = ["text1.txt", "text2.txt"]
>>> output = "\n".join([",".join([line.strip() for line in open(fn).readlines()]) for fn in files])
>>> output
'abcdef,xyz\n123456,1098'
>>>

[thistle]

I added 2 lines to the code. it was working some hours ago, but now it doesn't work. I don't know the problem!!!!!!!!!!!can anybody help?

import os,shutil
path = 'فناوري'
f=open("wwww.txt","a", encoding = 'utf-8')
for r,d,fi in os.walk(path):
    for files in fi:
        if files.endswith(".txt"):
             g=open(os.path.join(r,files), encoding = 'utf-8')
             for line in g:
                 f.write(line.strip('\n') + ' ')
                 shutil.copyfileobj(g,f)
                 f.write('\n')
                 g.close()
f.close()

[bvdet]

Please provide the error traceback or describe the issue.

[bvdet]

Just noticed something. Eliminate the for loop on the file object g. shutil.copyfileobj() copies all of the file contents, not just the current line. Something like this:

        if files.endswith(".txt"):
            g=open(os.path.join(r,files)) #, encoding='utf-8')
            shutil.copyfileobj(g,f)
            f.write('\n')
            g.close()

[thistle]

I want each file (which has some lines) to be written in just one line. so I need to omit newlines between them. and the to write the next file as the next line I need to add '\n'. so I cant eliminate for loop. If I eliminate it of course it merges them but there are a lot of lines. each file should be = one line

[bvdet]

Did you try the code in my first reply? That's the functionality you seek, or is it not? It uses a comma delimiter for lines in a file, but you can change that to whatever character you want.

[thistle]

I started python recently. sorry for so much questions. open (fn)reads a file but I have a folder which contains 10 files. what should I write instead of fn so that it reads the folder. I know I have to split the folder first with os.listdir (folder) but then what?

[bvdet]

Create the list of file names first. Then iterate on the list of file names.

import os
path = r"X:\temp\macro\test"
files = os.listdir(path)
outputList = []
for fn in files:
    if fn.endswith("txt"):
        outputList.append(",".join([line.strip() for line in open(os.path.join(path, fn)).readlines()]))
output = "\n".join(outputList)
print output