how to keep script running despite urlib.error.HTTPerror, http.client.HTTPResponse o

[gintare]

I would like that script would keep running, i.e. requesting urls with different words, depite errors.
Currently script stops running if error occurs.

#word comes from the list of words
res6="http://glosbe.com/en/el/"+word
try:
  resp = urllib.request.urlopen(res)
  if resp.getcode() == 200:
      html = resp.read()
      #proceed with result...
except urlib.error.HTTPerror as e :
  print(str(e.getcode()))
  #proceed with error...

[bvdet]

Encapsulate the request for urls in a while loop. Break the loop with a valid result to proceed.

[gintare]

Thanks. The final code looks like:

 
    #word comes from the list of words
    res6="http://glosbe.com/en/el/"+word
    try:
      while(urllib.request.urlopen(res)):
        resp = urllib.request.urlopen(res)
        if resp.getcode() == 200 : break 
      if resp.getcode() == 200:
      html = resp.read()
      #proceed with result...
    except urllib.error.HTTPError as e :
      #proceed with error...