How to check if the element is contained in list or not?

[Jimmy45]

Hello,

I have some problem with checking if the element is contained in the list or not.

For example:
a = ['abc', 'def', 'gh', 'i']
b = 'abc'

Following is my code:

def is_proper_word(b, a) :
 
    is_proper = False
    for b in proper_word_list:
        is_proper = True
    return is_proper
 

Is it correct?

Thank you in advance.

[Glenton]

Hi

With a and b as you suggest

b in a

returns True.

It seems unnecessary to do more work than this single line, but if you have a reason post back.

Actually post back anyway to let us know how it goes.

[Glenton]

By the way, your code would not work. It would simply create a loop of all the variables in proper_word_list, (which isn't defined anyway), calling the items in the list variable b. It would just over-write the b variable that you input.

[Nonemsludo]

@Jimmy45
You could use list comprehension,
[elem for elem in a if elem == b]

[Glenton]

Oh, if you're wanting to do it that way, you could use numpy arrays with a in b giving a boolean numpy array. Depends what you want to do really.