formatting list -> comma separated

[Robert]

given d:

d = ["soep", "reeds", "ook"]

I want it to print like

soep, reeds, ook

I've come up with :

print ("%s"+", %s"*(len(d)-1)) % tuple(d)

but this fails for d = []

any (pythonic) options for this?

Robert

[Jerry Hill]

On Wed, Jul 9, 2008 at 3:23 PM, Robert <rw*******@xs4all.nlwrote:

given d:
d = ["soep", "reeds", "ook"]

I want it to print like
soep, reeds, ook

use the join() method of strings, like this:

>>d = ["soep", "reeds", "ook"]
', '.join(d)

'soep, reeds, ook'

>>d = []
', '.join(d)

''

>>>

--
Jerry

[Paul Hankin]

On Jul 9, 8:23*pm, "Robert" <[e-mail]:

given d:

d = ["soep", "reeds", "ook"]

I want it to print like

soep, reeds, ook

I've come up with :

print ("%s"+", %s"*(len(d)-1)) % tuple(d)

but this fails for d = []

any (pythonic) options for this?

print ', '.join(d)

--
Paul Hankin

[norseman]

Robert wrote:

given d:

d = ["soep", "reeds", "ook"]

I want it to print like

soep, reeds, ook

I've come up with :

print ("%s"+", %s"*(len(d)-1)) % tuple(d)

but this fails for d = []

any (pythonic) options for this?

Robert

--
http://mail.python.org/mailman/listinfo/python-list

================================
the old fashion way would be:

d = ["soep", "reeds", "ook"]
if len(d) 0:
print ("%s"+", %s"*(len(d)-1)) % tuple(d)

# if d= [] then print stmnt bypassed

Steve
no******@hughes.net