converting to an integer

[Patrick C]

hey everyone, i'm having a mental block can anyone help me out

if i have a list like this
num = ['1;3;2;3;2;1;4', '\n', '30;2;13;2;1;4;2', '2;3;2;1;4;2;4', '3;2;1;4;2;4;1', '2;1;4;2;4;1;4', '1;4;2;4;1;4;2']

how might i get python to recognize each elemant as an integer so that i can sum each list

that is have it print
16
\n
54
18

etc

thanks

[bvdet]

>>> num = ['1;3;2;3;2;1;4', '\n', '30;2;13;2;1;4;2', '2;3;2;1;4;2;4', '3;2;1;4;2;4;1', '2;1;4;2;4;1;4', '1;4;2;4;1;4;2']
>>> s = '\n'.join([str(result) for result in [sum([int(i) for i in item.split(';')]) for item in num if item != '\n']])
>>> s
'16\n54\n18\n17\n18\n18'
>>> print s
16
54
18
17
18
18
>>> 

[Patrick C]

that works well, but i'm trying to keep a blank line if the '\n' was there to begin with, how can i tweak that so the solution would have been

'16\n\n54\n18\n17\n18\n18'

thanks

[bvdet]

results = []
for item in num:
    if item == '\n':
        results.append('')
    else:
        results.append(str(sum([int(i) for i in item.split(';')])))
print '\n'.join(results)

>>> 16
 
54
18
17
18
18
>>> print repr('\n'.join(results))
'16\n\n54\n18\n17\n18\n18'
>>> 

I got carried away with the list comprehension in my previous post. s could be:

s = '\n'.join([str(sum([int(i) for i in item.split(';')])) for item in num if item != '\n'])

[Patrick C]

hey thanks for breaking it up onto many lines, i'm so fresh at this that when it's all squeezed into one line my mind breaks