Accessing dictionary variable data

[psbasha]

The following example shows the storing of the data and accessing the data from dictionary variable.The accessing of dictionary variable data is not a orderas what we are storing.

Is my understanding is correct?.Is it possible to retrievethe dictiondary variable data in a order,as what we store?

Thanks in advance
PSB

>>> dict1= {"E1":[1,2,6,5],"E2":[2,3,7,6],"E3":[3,4,8,7],"E4":[5,6,10,9],"E5":[6,7,11,10],"E6":[7,8,12,11]}
>>> print dict1
{'E5': [6, 7, 11, 10], 'E4': [5, 6, 10, 9], 'E6': [7, 8, 12, 11], 'E1': [1, 2, 6, 5], 'E3': [3, 4, 8, 7], 'E2': [2, 3, 7, 6]}
>>> 

[ghostdog74]

The following example shows the storing of the data and accessing the data from dictionary variable.The accessing of dictionary variable data is not a orderas what we are storing.

Is my understanding is correct?.Is it possible to retrievethe dictiondary variable data in a order,as what we store?

Thanks in advance
PSB

>>> dict1= {"E1":[1,2,6,5],"E2":[2,3,7,6],"E3":[3,4,8,7],"E4":[5,6,10,9],"E5":[6,7,11,10],"E6":[7,8,12,11]}
>>> print dict1
{'E5': [6, 7, 11, 10], 'E4': [5, 6, 10, 9], 'E6': [7, 8, 12, 11], 'E1': [1, 2, 6, 5], 'E3': [3, 4, 8, 7], 'E2': [2, 3, 7, 6]}
>>> 

the typical way to do it is by sorting the keys

>>> for keys in sorted(dict1.keys()):
...  print keys, dict1[keys]
...
E1 [1, 2, 6, 5]
E2 [2, 3, 7, 6]
E3 [3, 4, 8, 7]
E4 [5, 6, 10, 9]
E5 [6, 7, 11, 10]
E6 [7, 8, 12, 11]
 
 

[psbasha]

In this example the data is available in a order.But if the data is available in this order.

dict1= {E2":[2,3,7,6],"E3":[3,4,8,7],"E1":[1,2,6,5],","E4":[5,6,10,9],"E5":[6,7,11,10],"E6":[7,8,12,11],"E3":[3,4,8,7]}

Thanks
PSB

[bartonc]

In this example the data is available in a order.But if the data is available in this order.

dict1= {E2":[2,3,7,6],"E3":[3,4,8,7],"E1":[1,2,6,5],","E4":[5,6,10,9],"E5":[6,7,11,10],"E6":[7,8,12,11],"E3":[3,4,8,7]}

Thanks
PSB

Dictionaries are NOT ordered collections. They are ramdomized for faster retreival (hashing).

[ghostdog74]

In this example the data is available in a order.But if the data is available in this order.

dict1= {E2":[2,3,7,6],"E3":[3,4,8,7],"E1":[1,2,6,5],","E4":[5,6,10,9],"E5":[6,7,11,10],"E6":[7,8,12,11],"E3":[3,4,8,7]}

Thanks
PSB

pls explain clearly. do you want to sort the keys ? or the dictionary values?
sort the keys means you want E1, then E2 and so on. Sort the values means for example, you want to sort [2,3,7,6] to become [2,3,6,7]

[bvdet]

The following example shows the storing of the data and accessing the data from dictionary variable.The accessing of dictionary variable data is not a orderas what we are storing.

Is my understanding is correct?.Is it possible to retrievethe dictiondary variable data in a order,as what we store?

Thanks in advance
PSB

>>> dict1= {"E1":[1,2,6,5],"E2":[2,3,7,6],"E3":[3,4,8,7],"E4":[5,6,10,9],"E5":[6,7,11,10],"E6":[7,8,12,11]}
>>> print dict1
{'E5': [6, 7, 11, 10], 'E4': [5, 6, 10, 9], 'E6': [7, 8, 12, 11], 'E1': [1, 2, 6, 5], 'E3': [3, 4, 8, 7], 'E2': [2, 3, 7, 6]}
>>> 

If you want to retrieve the data in the same order it was stored, you can use lists or tuples.

>>> keyList = ["E1", "E2", "E3", "E4"]
>>> dataList = [[1,2,6,5],[2,3,7,6],[3,4,8,7],[5,6,10,9]]
>>> for i, key in enumerate(keyList):
...     print '%s = %s' % (key, dataList[i])
...     
E1 = [1, 2, 6, 5]
E2 = [2, 3, 7, 6]
E3 = [3, 4, 8, 7]
E4 = [5, 6, 10, 9]
>>> 

A dictionary stores data randomly. Data items can be appended to lists as they are acquired. Retrieving dictionary data from a sorted key list will not necessarily match the order of data acquisition.

Is this what you are trying to do?

[psbasha]

Hi,

Thanks for the reply

Yes,You are right.

PSB