More elegant to get a name: o.__class__.__name__

[alf]

Hi,
is there a more elegant way to get o.__class__.__name__. For instance I
would imagine name(o).

--
alf

[Carl Banks]

alf wrote:

Hi,
is there a more elegant way to get o.__class__.__name__. For instance I
would imagine name(o).

def name_of_type(o):
return o.__class__.__name__

name_of_type(o)
Carl Banks

P.S. name(o) suggests it's the name of the object, not the type
P.P.S. you could use type(o).__name__ but it doesn't work for old-style
classes

[Paul McGuire]

"alf" <ask@mewrote in message
news:z7******************************@comcast.com. ..

Hi,
is there a more elegant way to get o.__class__.__name__. For instance I
would imagine name(o).

--
alf

>>name = lambda o : o.__class__.__name__
name(1)

'int'

Go for it!

-- Paul

[George Sakkis]

Carl Banks wrote:

alf wrote:

Hi,
is there a more elegant way to get o.__class__.__name__. For instance I
would imagine name(o).

def name_of_type(o):
return o.__class__.__name__

name_of_type(o)
Carl Banks

P.S. name(o) suggests it's the name of the object, not the type
P.P.S. you could use type(o).__name__ but it doesn't work for old-style
classes

You mean it doesn't work for old-style instances; OTOH __class__
doesn't work for old style classes:

>>class X: pass

....

>>X.__class__

AttributeError: class X has no attribute '__class__'

So to handle all cases, you'd have to go with:

def typename(o):
try: cls = o.__class__
except AttributeError: cls = type(o)
return cls.__name__
# or for fully qualified names
# return '%s.%s' % (cls.__module__, cls.__name__)

George

[alf]

alf wrote:

Hi,
is there a more elegant way to get o.__class__.__name__. For instance I
would imagine name(o).

decided to stick to o.__class__.__name__ for readibility.

--
alfz1