C++ to python with boost.python: Exposing virtual bool operator()(int)=0

[Pedro]

Hello pythonians! ;-D ,

I have a little problem when I expose (assisted by boost.python) classes
with virtual functions, specially with operator().
In the C++ code below I test two different implementations of a member
function of A that
takes as an argument the abstract class Base (see Option 1 / Option 2):
- Both compile without problems
- Only the second works in python (see python program below).

It seems like if the problem is in the way I expose operator()... but I
do not understand it very well
Any clue about why this is happening?I would appreciate any comment on this.
Thank you very much in advance. :-D

Pedro.
//.................................................. .....
//................ C++ code......................
//.................................................. .....
#include <boost/python.hpp>
#define OPTION1
//#undef OPTION1

struct Base
{
virtual ~Base() {}
virtual int f() = 0; // Like in
Boost.python tutorial
virtual int g(int) = 0; // With 1 argument
virtual bool operator()(int ii) =0; // __call__ - type function
};

class A{
private:
int v_;
public: A(int v): v_(v){}
#ifdef OPTION1
/* Option 1 */ int fun(Base& c) const { return
c(v_)?(c.g(v_)+c.f()):33; }
#else
/* Option 2 */ int fun(Base& c) const { return (c.g(v_)+c.f()); }
#endif
};

//:::::::::::::::::::::::::::BOOST::PYTHON in
action:::::::::::::::::::::::::::
using namespace boost::python;

struct BaseWrap : Base, wrapper<Base>
{
int f(){return call<int>(this->get_override("f").ptr());}
int g(int ii){return call<int>(this->get_override("g").ptr(),ii);}
bool operator()(int ii){ return
call<bool>(this->get_override("operator()").ptr(),ii);}
};

BOOST_PYTHON_MODULE(test2py)
{
class_<A>("A",init<int>())
.def("fun",&A::fun);

class_<BaseWrap, boost::noncopyable>("Base")
.def("f", pure_virtual(&Base::f))
.def("g", pure_virtual(&Base::g))
.def("__call__", pure_virtual(&Base::operator())) ;
};
//.................................................. .....
//................ Python code...................
//.................................................. .....

from test2py import *
## Extension of C++ class in python
class Derived(Base):
def f(self):
return 44
def g(self,n):
return n
def __call__(self, v):
return (v<23)
d=Derived()
print d.f()
print d.g(3)
print "is 20<23 and 24<23", d(20), d(24)
a=A(20)
print a.fun(d)

b=A(24)
print b.fun(d)
//.................................................. ....................
//................ Executing Python code..................
//.................................................. ...................
With Option 1 IS NOT WORKING!!
...
int fun(Base& c) const { return c(v_)?(c.g(v_)+c.f()):33; }
...

44
3
is 20<23 and 24<23 True False
Traceback (most recent call last):
File "d:\My_Documents\src\pysource\test.py", line 29, in ?
print a.fun(d)
TypeError: 'NoneType' object is not callable
With Option 2 IS WORKING!!
...
int fun(Base& c) const { return (c.g(v_)+c.f()); }
...
44
3
is 20<23 and 24<23 True False
64
68