I want to create a list of lists, each of which is identical, but which
can be modified independently i.e: x = [ [0], [0], [0] ]
x[0].append(1)
x
[[0, 1], [0], [0]]
The above construct works if I have only few items, but if I have many,
I'd prefer to write N =3
x =N*[[0]]
x
[[0], [0], [0]]
If I now try extending the lists indepently, I cannot, as they all
point to the same list object x[0].append(1)
x
[[0, 1], [0, 1], [0, 1]]
Is there a simple way to create a list of independent lists?
Thanks in advance
Thomas Philips 3  1901 
Ciao, tk****@hotmail.com! Che stavi dicendo? Is there a simple way to create a list of independent lists?
N=3
x=[[0] for e in range(N)]
--
Up da 1 giorno, 3 ore, 43 minuti e 10 secondi
> The above construct works if I have only few items, but if I have many, I'd prefer to write
N =3
x =N*[[0]]
x
[[0], [0], [0]]
If I now try extending the lists indepently, I cannot, as they all
point to the same list object
x[0].append(1)
x
[[0, 1], [0, 1], [0, 1]]
Is there a simple way to create a list of independent lists?
My first thought would be
N = 10
x = [[0] for _ in range(N)]
x[0].append(1)
x
[[0, 1], [0], [0], [0], [0], [0], [0], [0], [0], [0]]
HTH,
-tkc tk****@hotmail.com wrote: I want to create a list of lists, each of which is identical, but which
can be modified independently i.e:
x = [ [0], [0], [0] ]
x[0].append(1)
x [[0, 1], [0], [0]]
The above construct works if I have only few items, but if I have many,
I'd prefer to write N =3
x =N*[[0]]
x [[0], [0], [0]]
If I now try extending the lists indepently, I cannot, as they all
point to the same list object x[0].append(1)
x
[[0, 1], [0, 1], [0, 1]]
Is there a simple way to create a list of independent lists?
Try this...
x, y, value = 3, 3, 0
L = [[value]*x for i in xrange(y)]
Cheers,
Ron This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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