Is this a refrence issue?

[KraftDiner]

I understand that everything in python is a refrence....

I have a small problem..

I have a list and want to make a copy of it and add an element to the
end of the new list,
but keep the original intact....

so:
tmp = myList
tmp.append(something)
print tmp, myList

should be different...

[Carl J. Van Arsdall]

KraftDiner wrote:

I understand that everything in python is a refrence....

I have a small problem..

I have a list and want to make a copy of it and add an element to the
end of the new list,
but keep the original intact....

so:
tmp = myList

tmp = myList is a shallow copy
tmp.append(something)
print tmp, myList

should be different...

Therefore it shouldn't be different.

What you could do is make a second list
tmp = []

And then use the extend method:

tmp.extend(myList)
tmp.append(someEntry)

This would give you what you want, and there's more than one way to do this.

-carl

--

Carl J. Van Arsdall
cv*********@mvista.com
Build and Release
MontaVista Software

[Mike Meyer]

"KraftDiner" <bo*******@yahoo.com> writes:

I understand that everything in python is a refrence....
Correct.
I have a small problem..
Maybenot so small.
I have a list and want to make a copy of it and add an element to the
end of the new list,
but keep the original intact....

so:
tmp = myList
tmp.append(something)
print tmp, myList

should be different...

They won't be, because the assignment statement just binds the name on
the left to the value on the right, meaning they'll both point to the
same object. To get a copy, you have to make a copy. The easy way is:

tmp = list(myList)

However, this won't coppy the things *in* myList. If you want that you
want the copy module's deepcopy function.

<mike
--
Mike Meyer <mw*@mired.org> http://www.mired.org/home/mwm/
Independent WWW/Perforce/FreeBSD/Unix consultant, email for more information.

[James Tanis]

On 12/28/05, Carl J. Van Arsdall <cv*********@mvista.com> wrote:

KraftDiner wrote:

I understand that everything in python is a refrence....

I have a small problem..

I have a list and want to make a copy of it and add an element to the
end of the new list,
but keep the original intact....

so:
tmp = myList

tmp = myList is a shallow copy

tmp.append(something)
print tmp, myList

should be different...

Therefore it shouldn't be different.

What you could do is make a second list
tmp = []

And then use the extend method:

tmp.extend(myList)
tmp.append(someEntry)

This would give you what you want, and there's more than one way to do this.

Such as from the python docs..

import copy

x = copy.copy(y) # make a shallow copy of y
x = copy.deepcopy(y) # make a deep copy of y
-carl

--

Carl J. Van Arsdall
cv*********@mvista.com
Build and Release
MontaVista Software

--
http://mail.python.org/mailman/listinfo/python-list

--
James Tanis
jt****@pycoder.org
http://pycoder.org

[Steven D'Aprano]

On Wed, 28 Dec 2005 14:40:45 -0800, Carl J. Van Arsdall wrote:

KraftDiner wrote:

I understand that everything in python is a refrence....

I have a small problem..

I have a list and want to make a copy of it and add an element to the
end of the new list,
but keep the original intact....

so:
tmp = myList

tmp = myList is a shallow copy

tmp = myList *is not a copy at all*.

The *names* "tmp" and "myList" both are bound to the *same* object. They
are two names for the same object.

tmp = myList[:] is a shallow copy of myList.

tmp = copy.deepcopy(myList) makes a copy of myList, *and* copies of
everything inside myList.

--
Steven.

[Scott David Daniels]

KraftDiner wrote:

I have a list and want to make a copy of it and add an element
to the end of the new list, but keep the original intact....

Nobody has mentioned the obvious yet:

tmp = myList + [something]

--Scott David Daniels
sc***********@acm.org