I have have the following code: a=[3,5,8,0]
b={}
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks! 20  1934 
b = dict([(x,dict()) for x in a])
Shi Mu wrote: I have have the following code: a=[3,5,8,0]
b={}
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
b = dict([(x,dict()) for x in a])
Shi Mu wrote: I have have the following code: a=[3,5,8,0]
b={}
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
On 20 Nov 2005 02:59:30 -0800, bo****@gmail.com <bo****@gmail.com> wrote: b = dict([(x,dict()) for x in a])
Shi Mu wrote: I have have the following code:>> a=[3,5,8,0]
>> b={}
>>
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
Thanks!!!
On 20 Nov 2005 02:59:30 -0800, bo****@gmail.com <bo****@gmail.com> wrote: b = dict([(x,dict()) for x in a])
Shi Mu wrote: I have have the following code:>> a=[3,5,8,0]
>> b={}
>>
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
Thanks!!!
Shi Mu <sa************@gmail.com> wrote: I have have the following code: a=[3,5,8,0]
b={}
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Explicit:
a = [3, 5, 8, 0]
b = {}
for key in a:
b[key] = []
Quicker:
a = [3, 5, 8, 0]
b = dict( [(k, []) for k in a] )
What behaviour do you expect when there are repeated values in the
list 'a'?
--
\ "Faith may be defined briefly as an illogical belief in the |
`\ occurrence of the improbable." -- Henry L. Mencken |
_o__) |
Ben Finney
Shi Mu <sa************@gmail.com> wrote: I have have the following code: a=[3,5,8,0]
b={}
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Explicit:
a = [3, 5, 8, 0]
b = {}
for key in a:
b[key] = []
Quicker:
a = [3, 5, 8, 0]
b = dict( [(k, []) for k in a] )
What behaviour do you expect when there are repeated values in the
list 'a'?
--
\ "Faith may be defined briefly as an illogical belief in the |
`\ occurrence of the improbable." -- Henry L. Mencken |
_o__) |
Ben Finney
Uzytkownik "Shi Mu" <sa************@gmail.com> napisal w wiadomosci
news:ma**************************************@pyth on.org...
I have have the following code: a=[3,5,8,0]
b={}
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
Other solution:
b.fromkeys(a,[])
cheers,
Przemek
Uzytkownik "Shi Mu" <sa************@gmail.com> napisal w wiadomosci
news:ma**************************************@pyth on.org...
I have have the following code: a=[3,5,8,0]
b={}
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
Other solution:
b.fromkeys(a,[])
cheers,
Przemek
przemek drochomirecki wrote: Uzytkownik "Shi Mu" <sa************@gmail.com> napisal w wiadomosci
news:ma**************************************@pyth on.org...
I have have the following code: a=[3,5,8,0]
b={}
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
Other solution:
b.fromkeys(a,[])
Be warned that all keys share the same value.
a = [3, 5, 8, 0]
b = dict.fromkeys(a, [])
b[3].append(42)
b
{8: [42], 0: [42], 3: [42], 5: [42]}
Probably not what you want...
Peter
przemek drochomirecki wrote: Uzytkownik "Shi Mu" <sa************@gmail.com> napisal w wiadomosci
news:ma**************************************@pyth on.org...
I have have the following code: a=[3,5,8,0]
b={}
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
Other solution:
b.fromkeys(a,[])
Be warned that all keys share the same value.
a = [3, 5, 8, 0]
b = dict.fromkeys(a, [])
b[3].append(42)
b
{8: [42], 0: [42], 3: [42], 5: [42]}
Probably not what you want...
Peter
On 11/20/05, Peter Otten <__*******@web.de> wrote: przemek drochomirecki wrote:
Uzytkownik "Shi Mu" <sa************@gmail.com> napisal w wiadomosci
news:ma**************************************@pyth on.org...
I have have the following code:> a=[3,5,8,0]
> b={}
>
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
Other solution:
b.fromkeys(a,[])
Be warned that all keys share the same value.
a = [3, 5, 8, 0]
b = dict.fromkeys(a, [])
b[3].append(42)
b
{8: [42], 0: [42], 3: [42], 5: [42]}
Probably not what you want...
Peter
how to do with it?
On 11/20/05, Peter Otten <__*******@web.de> wrote: przemek drochomirecki wrote:
Uzytkownik "Shi Mu" <sa************@gmail.com> napisal w wiadomosci
news:ma**************************************@pyth on.org...
I have have the following code:> a=[3,5,8,0]
> b={}
>
How I can i assign each item in a as the key in the dictionary b
simultaneously?
that is,
b={3:[],5:[],8:[],0:[]}
Thanks!
Other solution:
b.fromkeys(a,[])
Be warned that all keys share the same value.
a = [3, 5, 8, 0]
b = dict.fromkeys(a, [])
b[3].append(42)
b
{8: [42], 0: [42], 3: [42], 5: [42]}
Probably not what you want...
Peter
how to do with it?
Shi Mu wrote: how to do with it?
Use Ben Finney's, not Przemek's approach if the values are mutables that you
plan to modify. If that's what you are asking.
Peter
Shi Mu wrote: how to do with it?
Use Ben Finney's, not Przemek's approach if the values are mutables that you
plan to modify. If that's what you are asking.
Peter
Uzytkownik "Peter Otten" <__*******@web.de> napisal w wiadomosci
news:dl*************@news.t-online.com... Shi Mu wrote:
how to do with it?
Use Ben Finney's, not Przemek's approach if the values are mutables that
you plan to modify. If that's what you are asking.
Peter
Maybe he just want to use dictionary as a set.
He can use SET container instead.
Przemek
Uzytkownik "Peter Otten" <__*******@web.de> napisal w wiadomosci
news:dl*************@news.t-online.com... Shi Mu wrote:
how to do with it?
Use Ben Finney's, not Przemek's approach if the values are mutables that
you plan to modify. If that's what you are asking.
Peter
Maybe he just want to use dictionary as a set.
He can use SET container instead.
Przemek
On 11/20/05, przemek drochomirecki <dr*****@wytnij.hyene.com> wrote:
Uzytkownik "Peter Otten" <__*******@web.de> napisal w wiadomosci
news:dl*************@news.t-online.com... Shi Mu wrote:
how to do with it?
Use Ben Finney's, not Przemek's approach if the values are mutables that
you plan to modify. If that's what you are asking.
Peter
Maybe he just want to use dictionary as a set.
He can use SET container instead.
Przemek
How to use SET?
On 11/20/05, przemek drochomirecki <dr*****@wytnij.hyene.com> wrote:
Uzytkownik "Peter Otten" <__*******@web.de> napisal w wiadomosci
news:dl*************@news.t-online.com... Shi Mu wrote:
how to do with it?
Use Ben Finney's, not Przemek's approach if the values are mutables that
you plan to modify. If that's what you are asking.
Peter
Maybe he just want to use dictionary as a set.
He can use SET container instead.
Przemek
How to use SET?
Uzytkownik "Shi Mu" <sa************@gmail.com> napisal w wiadomosci
news:ma**************************************@pyth on.org...
On 11/20/05, przemek drochomirecki <dr*****@wytnij.hyene.com> wrote:
Uzytkownik "Peter Otten" <__*******@web.de> napisal w wiadomosci
news:dl*************@news.t-online.com... Shi Mu wrote:
how to do with it?
Use Ben Finney's, not Przemek's approach if the values are mutables that
you plan to modify. If that's what you are asking.
Peter
Maybe he just want to use dictionary as a set.
He can use SET container instead.
Przemek
How to use SET? http://docs.python.org/lib/types-set.html a
[3, 5, 8, 8] b = set(a)
b
set([8, 3, 5])
cheers,
przemek
Uzytkownik "Shi Mu" <sa************@gmail.com> napisal w wiadomosci
news:ma**************************************@pyth on.org...
On 11/20/05, przemek drochomirecki <dr*****@wytnij.hyene.com> wrote:
Uzytkownik "Peter Otten" <__*******@web.de> napisal w wiadomosci
news:dl*************@news.t-online.com... Shi Mu wrote:
how to do with it?
Use Ben Finney's, not Przemek's approach if the values are mutables that
you plan to modify. If that's what you are asking.
Peter
Maybe he just want to use dictionary as a set.
He can use SET container instead.
Przemek
How to use SET? http://docs.python.org/lib/types-set.html a
[3, 5, 8, 8] b = set(a)
b
set([8, 3, 5])
cheers,
przemek This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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