Numeric - Multiply a byte array by a float.

[Kamilche]

I have a need to multiply all the bytes in a Numeric array, by a
float, such as .9, .8, etc. I can't figure out a way to do that.

Does anyone have a clue how this is accomplished? I need the resulting
array to be truncated to an array of bytes.

Thanks!

--Kamilche

[Christopher T King]

On 13 Jul 2004, Kamilche wrote:

I have a need to multiply all the bytes in a Numeric array, by a
float, such as .9, .8, etc. I can't figure out a way to do that.
By "all the bytes in a Numeric array", I'm assuming you mean you have an
Int8 or UInt8 array. Correct me if I'm wrong.
Does anyone have a clue how this is accomplished? I need the resulting
array to be truncated to an array of bytes.

This should work, assuming my above assumption is correct:

byte_array = array([1,2,3,4,5,6],Int8)
byte_array = (byte_array*.5).astype(Int8)