Getting a number out of a string

[ssmith579]

I'm trying to extract single digit number from a string.

t[1] = '06897'

I want to get the 7, 9,8 & 6 seperated out to use but can't find a way
to split out the single characters.

Thanks

[jepler]

You can index into a string:

s = '06897'
s[2] '8'

You can also turn each character into an integer, in various ways: [int(c) for c in s] [0, 6, 8, 9, 7] map(int, s)

[0, 6, 8, 9, 7]

Jeff

-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.4.1 (GNU/Linux)

iD8DBQFDOY7JJd01MZaTXX0RAnvrAJ9jK6aatByJuCiXXH4bBP iXHf+iegCgiP9h
3rDgupFxC1qWK9czpUayhIo=
=qR27
-----END PGP SIGNATURE-----

[Claudio Grondi]

what about:

lst = [digit for digit in '06897']
lst

['0', '6', '8', '9', '7']

Claudio

<ss*******@aol.com> schrieb im Newsbeitrag
news:11**********************@g47g2000cwa.googlegr oups.com... I'm trying to extract single digit number from a string.

t[1] = '06897'

I want to get the 7, 9,8 & 6 seperated out to use but can't find a way
to split out the single characters.

Thanks

[Will McGugan]

Claudio Grondi wrote:

what about:

lst = [digit for digit in '06897']
lst
['0', '6', '8', '9', '7']

Or..

list('06897')

['0', '6', '8', '9', '7']

Will McGugan
--
http://www.willmcgugan.com
"".join({'*':'@','^':'.'}.get(c,0) or chr(97+(ord(c)-84)%26) for c in
"jvyy*jvyyzpthtna^pbz")

[ssmith579]

Thanks all! This is just what I needed.

[Steven D'Aprano]

On Tue, 27 Sep 2005 20:28:53 +0000, Claudio Grondi wrote:

what about:

lst = [digit for digit in '06897']
lst

['0', '6', '8', '9', '7']

No need to use a list comprehension when this works just as well:

py> list('06897')
['0', '6', '8', '9', '7']

--
Steven.