How does this code works:

[vch]

Here's an example from some book:

def foo(n):
s = [n]
def bar(i):
s[0] += i
return s[0]
return bar

what I don't understand is how this example works, taking into account
the LGB rule. I thought that s is not accessible from bar, but it is,
apparently. Why?

[Robert Kern]

vch wrote:

Here's an example from some book:

def foo(n):
s = [n]
def bar(i):
s[0] += i
return s[0]
return bar

what I don't understand is how this example works, taking into account
the LGB rule. I thought that s is not accessible from bar, but it is,
apparently. Why?

Python now has nested scopes.

http://www.python.org/peps/pep-0227.html

--
Robert Kern
rk***@ucsd.edu

"In the fields of hell where the grass grows high
Are the graves of dreams allowed to die."
-- Richard Harter

[Rocco Moretti]

vch wrote:

Here's an example from some book:

def foo(n):
s = [n]
def bar(i):
s[0] += i
return s[0]
return bar

what I don't understand is how this example works, taking into account
the LGB rule. I thought that s is not accessible from bar, but it is,
apparently. Why?

Nested Scopes (Since Python 2.1):

http://www.python.org/peps/pep-0227.html