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Type Casting

2 New Member
Hi could anyone guide to convert the below expression as integer


$number="(3+4)*(5+6)";
May 28 '12 #1
3 2308
RonB
589 Recognized Expert Moderator Contributor
Take off the quotes.
May 28 '12 #2
Ranjith
2 New Member
Thanks, i aware about that but i would like to know how to change $number="(3+4)*(5+6)"; this format as integer.without taking the quotes..
May 31 '12 #3
RonB
589 Recognized Expert Moderator Contributor
You don't need to do anything. Perl is not strongly typed, so there's no casting that needs to be done by you. It's based on the context in which you use the var.

Can you provide a code snippet where you think you need the type casting and explain the problem that you're seeing?
May 31 '12 #4

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