split function

[nivet]

Hi,

I am new to perl programming.

I have a requirement to validate the input received from the user with the file and send it to the printer.

For Eg:
script -o option -p printername -f filename

script - is the name of my script
-o option- is the option that has to be validated with another file
-p printername - is the name of my printer
-f filename - is the filename which has to be printed.

how to use this split function in this case. I want to take" -o option" and compare it with the file.
I already have a print queue ready. what is teh command to send the filename to the printer.

Please help me.

Thanks.

[nithinpes]

To process command line options, you can make use of GetOpt::Std module that comes with default Perl installation.

[nivet]

i had used the below command to check whether the file exists or not.
eventhough the file exists in proper path, it is going to else part.

or if the path is wrong, it is not dying....
Please help...

#!/usr/bin/perl
 
use strict;
 
my $file = <STDIN>;
print ( $file );
$ENV{'PPD'} = $file;
 
# file
 
open (FILE, $file) || die "cannot open";
 
if (-e $file) {
print "exists \n";
}
else
{
print ( $file );
print "not \n";
}
close(FILE);
 

[nithinpes]

i had used the below command to check whether the file exists or not.
eventhough the file exists in proper path, it is going to else part.

or if the path is wrong, it is not dying....
Please help...

#!/usr/bin/perl
 
use strict;
 
my $file = <STDIN>;
print ( $file );
$ENV{'PPD'} = $file;
 
# file
 
open (FILE, $file) || die "cannot open";
 
if (-e $file) {
print "exists \n";
}
else
{
print ( $file );
print "not \n";
}
close(FILE);

Do remember to chop the newline while taking input from command line/terminal. That will solve the issue.

chomp(my $file = <STDIN>);
 

[nivet]

Hi,

Thanks for the reply..

i have got the option from the user Eg: -o xxx=yyy

@options=@ARGV[0..$#ARGV];

I want to ignore -o and take only xxx in one variable and yyy in another variable..

Please help me with the commands..
Thank You.

[nithinpes]

If you are calling the script like,
perl script.pl -o xxx=yyy

use:

use strict;
my $option=$ARGV[1];     # get second argument
my ($first, $second) = split /=/,$option;   # split across '='
print "$first\n$second\n";
 

However, if you are handling multiple options, it is better to use Getopt::Std as I said before.

- Nithin

[nivet]

Hi Nithin,

Thank you for the reply.

this is what i exactly wanted.

perl script.pl -o xxx=yyy -o aaa=bbb -o asd=asd ........

i want to execute my script in this way...

so using getopt, returns only the last value.
and also i want to ignore -o and use only xxx=yyy, aaa=bbb, asd=asd values.
xxx,aaa,asd separately in a array and yyy,bbb,asd separately in a array......

please help me if you have any idea on this.

Thanks in advance...

[nithinpes]

Hi Nithin,

Thank you for the reply.

this is what i exactly wanted.

perl script.pl -o xxx=yyy -o aaa=bbb -o asd=asd ........

i want to execute my script in this way...

so using getopt, returns only the last value.
and also i want to ignore -o and use only xxx=yyy, aaa=bbb, asd=asd values.
xxx,aaa,asd separately in a array and yyy,bbb,asd separately in a array......

please help me if you have any idea on this.

Thanks in advance...

Try:

use strict;
 
my @options=grep(!/-o/,@ARGV); # get all args other than -o
my (@first,@second);
foreach(@options) {
my ($first, $second) = split /=/;
push @first,$first;
push @second,$second;
}
 

[nivet]

Thanks for this valuable information.
If there is any rating for the replies I would like to give you 10.
Thanks a lot.

[nivet]

I am executing the below script in the terminal.

/usr/lib/filter/rip "<some options>" /anyfilename > /outputfile

I am executing a script named rip with some options and giving the input file and redirecting it to a file.

I want to use perl script to execute this command.

I used system command as below.

system("/usr/lib/filter/rip "<some options>" /anyfilename > /outputfile");

It is not working. How to execute.
Please help.

[nivet]

I have executed the below command and it is partially working.

@pr = ("/usr/lib/rip","option","/test",">","/del");
print ( "@pr" );
system("@pr");

Bash#:/usr/lib/rip option /test > /del

This <option> has to be displayed in double quotes ("option").
But this double quotes are taken as space.

The command I want to execute is as below.

Bash#:/usr/lib/rip "option" /test > /del

Please help.

[nithinpes]

I have executed the below command and it is partially working.

@pr = ("/usr/lib/rip","option","/test",">","/del");
print ( "@pr" );
system("@pr");

Bash#:/usr/lib/rip option /test > /del

This <option> has to be displayed in double quotes ("option").
But this double quotes are taken as space.

The command I want to execute is as below.

Bash#:/usr/lib/rip "option" /test > /del

Please help.

The double quotes around options should be escaped. For ex., consider the command you need is

#path/rip "Hello man" input.txt  > output.txt
 

Then, the system command should be as below:

system("path/rip \"Hello man\" input.txt > output.txt");
 

[nivet]

Thanks for the reply.

I want to store the output file. If i store it in an $var or @array, the file is not saved properly.

my script:
my $file = "/tmp/input";
my @pr = "/tmp/file.log";

@command = ("/usr/lib/rip \"options\" $file > @pr");
system ( "@command" );

file.log shows some file size. When i try to open it, it is not responding.
please let me know how to solve this issue.
This issue is not present wen a txt file is given as input. other than text file all other files are giving problem.

Thanks,

[KevinADC]

my $file = '/tmp/input';
my $out = '/tmp/file.log';
 
my $command = ("/usr/lib/rip \"options\" $file > $out");
system ($command);