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System.Diagnostics.Process

9 New Member
I am opening a exe application on button click event its working fine but when i am going to click multiple times on button without closing exe file than it is opening number of times same programm.
I want to check and put the condition if 'ose.exe' is open then dont open another one.
if 'ose.exe' is not open then open it.

code:
-----
Private Sub BtnPro_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles BtnPro.Click

Dim P As System.Diagnostics.Process = New Process
Dim sPath As String = Application.StartupPath
sPath = "C:\Ume Projects\bin"
P.StartInfo.FileName = sPath & "\FreeVK.exe"
P.Start()
end sub

Thanks
Istiyaque
Aug 26 '10 #1
2 782
Plater
7,872 Recognized Expert Expert
So loop through the currently running processes and check to see if the one you are after is already open first? (You can probably tell it to become the active window too if you wanted)
Aug 31 '10 #2
Sfreak
64 New Member
Try something like:

Expand|Select|Wrap|Line Numbers
  1. //get this running process
  2. Process proc = Process.GetCurrentProcess();
  3. //get all other (possible) running instances
  4. Process[] processes = Process.GetProcessesByName(proc.ProcessName);
  5.  
  6. if (processes.Length > 1)
  7. {
  8.     //Do What you want
  9. }
  10. else
  11. {
  12.     MessageBox.Show("No other running applications found.");
  13. }
Hope this can help you

Fernando Mello
Aug 31 '10 #3

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